Question

我有一个字典列表

[{"id":1, "name": "jane", "contact": {"email": "jane@gmail.com", "phone": "8179482938"}},
{"id":2, "name": "john", "contact": {"email": "john@gmail.com", "phone": "8179482937"}},
{"id":3, "name": "june", "contact": {"email": "june@gmail.com", "phone": "8179482936"}}]

如何仅根据 jane 的电话号码 (8179482938) 找到她的索引？

Answer 1

比较简单。您遍历列表，直到找到您想要的那个。

def get_name(phone):
    for i, row in enumerate(list_of_dicts):
        if row['contact']['phone'] == phone:
            return i

Answer 2

这个：

book = [{"id":1, "name": "jane", "contact": {"email": "jane@gmail.com", "phone": "8179482938"}},
{"id":2, "name": "john", "contact": {"email": "john@gmail.com", "phone": "8179482937"}},
{"id":3, "name": "june", "contact": {"email": "june@gmail.com", "phone": "8179482936"}}]

for item in book:
    if item['contact']['phone'] == '8179482938':
        print(item['id'])

Answer 3

要获取索引，您可以执行以下操作（const classes = useStyles(); return ( <main className={classes.content}> <div className={classes.toolbar} /> <Grid container justify ="center" spacing={3}> {() => products.map((product) => ( <Grid item key={product.id}xs ={3} sm={6} md={4}> <Product product={product}/> </Grid> ))} </Grid> </main> ) } export default Products 是您的问题列表）：

lst

打印：

idx = next(i for i, d in enumerate(lst) if d["contact"]["phone"] == "8179482938")
print(idx)

根据字典的嵌套值在列表中查找嵌套字典的索引

3 个答案: