在我的项目中,我试图获取视频的 id,然后在我的视频中打开视频,但我在 3 分中挣扎
uploadVideo() async {
setState(() {
isuploading = true;
});
try {
var firebaseuseruid = FirebaseAuth.instance.currentUser.uid;
DocumentSnapshot userdoc = await FirebaseFirestore.instance
.collection('meinprofilsettings')
.doc(firebaseuseruid)
.get();
var alldocs = await FirebaseFirestore.instance.collection('videos').get();
int length = alldocs.docs.length;
String videourl = await uploadvideotostorage("Video $length");
String previewimage = await uploadimagetostorage("Video $length");
FirebaseFirestore.instance.collection('videos').doc("Video $length").set({
'username': userdoc.data()['username'],
'uid': firebaseuseruid,
'profilepic': userdoc.data()['url'],
'id':"Video $length",
'likes': [],
'commentcount': 0,
'sharecount': 0,
'hashtag1': hashtagcontroller.text,
'hashtag2': hashtagcontroller2.text,
'hashtag3': hashtagcontroller3.text,
'videourl': videourl,
'previewimage': previewimage,
'ratings': [],
});
Navigator.pop(context);
} catch (e) {
print(e.toString());
}
}
}
我想要的是视频的真实 id 而不是“视频 $length” 2. 如何在创建时访问 id,例如如何调用它? ? 3.我怎样才能用这个id创建一个新的集合,然后像这样保存一些数据,但是像这样 new collection=> videoed => new field with some data , new field with some data
这是我上传它的方式 图片为预览图片
getpreviewimage() async {
final previewimage = await flutterVideoCompress.getThumbnailWithFile(
widget.videopath_asstring,
);
return previewimage;
}
compressvideo() async {
if (widget.imageSource == ImageSource.gallery) {
return widget.videofile;
} else {
final compressvideo = await flutterVideoCompress.compressVideo(
widget.videopath_asstring,
quality: VideoQuality.MediumQuality);
return File(compressvideo.path);
}
}
uploadvideotostorage(String id) async {
final video = await allvideos.child(id).putFile(await compressvideo());
String url = await video.ref.getDownloadURL();
return url;
}
uploadimagetostorage(String id) async {
final video = await allimages.child(id).putFile(await getpreviewimage());
String url = await video.ref.getDownloadURL();
id=url;
return url;
}
答案 0 :(得分:0)
如果我理解正确,请将它们更改为如下所示:
Future<String> uploadvideotostorage(String id) async {
final video = await allvideos.child(id).putFile(await compressvideo());
String url = await video.ref.getDownloadURL();
return url;
}
Future<String> uploadimagetostorage(String id) async {
final video = await allimages.child(id).putFile(await getpreviewimage());
String url = await video.ref.getDownloadURL();
return url;
}
还有这个:
String videourl = await uploadvideotostorage(firebaseuseruid);
'id':videourl,
这是假设 compressvideo()
工作正常。