Question

我使用 swift run gradlew build，但它卡在 Start Daemom 上。

#!/usr/bin/swift sh

import Foundation


func shell(_ command: String) -> Void {
    let task = Process()
    task.standardOutput = FileHandle.standardOutput
    task.standardError = FileHandle.standardError
    task.standardInput = FileHandle.standardInput

    task.arguments = ["-c", command]
    task.launchPath = "/bin/sh"
    task.currentDirectoryPath = "/Users/MyProjectPath"
    task.launch()
    
    task.waitUntilExit()
    
    
    assert(task.terminationStatus == 0, "\(command)")
}




shell("./gradlew --debug --info :app:assembleRelease")

输出：

08:52:39.590 [DEBUG] [org.gradle.process.internal.DefaultExecHandle] Changing state to: STARTING
08:52:39.591 [DEBUG] [org.gradle.process.internal.DefaultExecHandle] Waiting until process started: Gradle build daemon.
08:52:39.601 [DEBUG] [org.gradle.process.internal.DefaultExecHandle] Changing state to: STARTED
08:52:39.602 [INFO] [org.gradle.process.internal.DefaultExecHandle] Successfully started process 'Gradle build daemon'
08:52:39.602 [DEBUG] [org.gradle.launcher.daemon.client.DefaultDaemonStarter] Gradle daemon process is starting. Waiting for the daemon to detach...
08:52:39.602 [DEBUG] [org.gradle.process.internal.ExecHandleRunner] waiting until streams are handled...
08:52:39.604 [DEBUG] [org.gradle.launcher.daemon.bootstrap.DaemonOutputConsumer] Starting consuming the daemon process output.

> Starting Daemon

它启动成功守护进程并等待守护进程输出，由于某种原因没有得到守护进程的输出。

Answer 1

根据苹果文档，task.launchPath 和 task.launch() 已“弃用”，不建议再使用。而是使用 task.executableURL 和 try task.run()。

Swift 运行 shell 命令卡住了，但在 xcode 调试中成功

1 个答案: