这是我正在谈论的场景:
let obj = {
id: "kjhgfr^&*()(*UY",
id: "kjhgfr^OIJHB",
id: "kjhgfr^)(*&^%Y",
id: "DFGHI(*&YTRDTYHKI*",
id: ")(IUHGVYUJKO))(*UY",
id: "VGYUKO(*UYH",
id: "BHYUIOP)(*&^T%",
id: "0987654567890",
id: "5678909876543",
};
我想用这样的 id 创建一个数组。
[
"5678909876543",
"0987654567890",
"VGYUKO(*UYH",
"kjhgfr^&*()(*UY",
"VGYUKO(*UYH",
];
答案 0 :(得分:2)
您的对象不正确。
可能与: Javascript object literal - possible to add duplicate keys?
因此,它将被覆盖以获取最后一个值。
let obj ={id:"kjhgfr^&*()(*UY",id:"kjhgfr^OIJHB",id:"kjhgfr^)(*&^%Y",id:"DFGHI(*&YTRDTYHKI*",id:")(IUHGVYUJKO))(*UY",id:"VGYUKO(*UYH",id:"BHYUIOP)(*&^T%",id:"0987654567890",id:"5678909876543",};
console.log(obj);
// { "id": "5678909876543"}
答案 1 :(得分:-1)
您不能有重复的密钥。每个相同的键都会覆盖之前定义的值。
你可以试试这个(假设你可以控制输入):
#include <iostream>
#include <string>
using namespace std;
int main() {
string ride;
int age, tp, sp;
double td;
//print outs and input
cout<<"What ride would you like to buy a ticket for? "<<endl;
cin>>ride;
cout<<"How old are you?"<<endl;
cin>>age;
这类似于以下问题:Read and loop through an object with non-unique key value pairs