我从下面代码的最后一行得到了堆栈溢出错误。我不明白为什么。有什么想法吗?
var slots = from a in db.AvailableAppointments
where a.RequestID == reqId
select new
DataLayer.DateAndTimeslot
{
date = a.Date.ToShortDateString(),
timeSlot = a.Timeslot
};
returnValue.DateAndTimeslot = slots.ToArray();
我的班级;
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Runtime.Serialization;
namespace DataLayer
{
[DataContract(Namespace = "http://wholesale.fluidata.co.uk/bt/AppointmentAvailabilityResponse")]
public class AppointmentAvailabilityResponse : DataLayer.WebserviceMessage
{
DateAndTimeslot[] _dateAndTimeSlot;
[DataMember]
public DateAndTimeslot[] DateAndTimeslot
{
get { return _dateAndTimeSlot; }
set { _dateAndTimeSlot = value; }
}
}
public class DateAndTimeslot
{
private String _date;
private String _timeSlot;
[DataMember]
public string date
{
get { return this._date; }
set {_date = value;}
}
[DataMember]
public string timeSlot
{
get { return this.timeSlot; }
set {_timeSlot = value;}
}
}
}
我的表格(带示例数据)
ID RequestID Date Timeslot
171 3214 2005-12-28 00:00:00.000 EV
172 3214 2005-12-28 00:00:00.000 EV
173 3214 2005-12-29 00:00:00.000 EV
174 3214 2005-12-29 00:00:00.000 EV
175 3214 2005-12-30 00:00:00.000 EV
176 3214 2005-12-30 00:00:00.000 EV
CREATE TABLE [dbo].[AvailableAppointments](
[ID] [int] IDENTITY(1,1) NOT NULL,
[RequestID] [int] NOT NULL,
[Date] [datetime] NOT NULL,
[Timeslot] [varchar](21) NOT NULL,
CONSTRAINT [PK_AvalibleAppointments] PRIMARY KEY CLUSTERED
(
[ID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
答案 0 :(得分:7)
下面:
[DataMember]
public string timeSlot
{
get { return this.timeSlot; }
set { _timeSlot = value; }
}
注意getter和递归调用中缺少_
?
应该是:
[DataMember]
public string timeSlot
{
get { return this._timeSlot; }
set { _timeSlot = value; }
}
顺便说一下,自从我开始在C#中使用Auto implemented properties以来,这些错误就被遗忘了:
[DataMember]
public string TimeSlot { get; set; }
只是一个挑剔的旁注:将属性名称以大写字母(TimeSlot
而不是timeSlot
)开头是一种很好的编码习惯。
答案 1 :(得分:3)
这是你的递归。您需要_
:get { return this.timeSlot; }
public string timeSlot
{
get { return this.timeSlot; }
set {_timeSlot = value;}
}