我的出发点是这里的 foo()
示例之类的方法。我正在使用 retries: 1
。
func foo() {
// create url ...
let urlRequest = URLRequest(for: url, httpMethod: "POST", resource: nil, token: accessToken)
let combineRequest = CombineRequest(auth: auth)
combineRequest.runWithResponseStatus(urlRequest, checkStatusCode: 201, retries: 1)
.sink { completion in
switch completion {
case .finished:
break
case .failure(let error):
self.toasts.insert(ToastText(type: .error, text: Text("\(error.localizedDescription)")), at: 0)
self.clearToasts()
}
} receiveValue: { _ in
// successful
}
.store(in: &cancellables)
}
所以这是一个 POST
合并请求 (runWithResponseStatus()
)。当我收到 401 - unauthorized
时,我想执行另一个合并请求 (refresh()
)。
refresh()
成功,它应该执行 auth.setAccessToken(to: newAccessToken.token)
并重试它之前调用的 (runWithResponseStatus()
) 方法一次。.failure
上,我正在执行 print("\(error.localizedDescription)")
,但我想在链中返回该错误,以便它以 foo()
方法结束,在那里我可以将其放入 toasts 数组中。有人知道如何实现这两点吗?如果可能的话,还可以利用联合收割机的力量让它更干净吗?
struct CombineRequest {
var auth: Auth
var jsonDecoder: JSONDecoder = JSONDecoder(dateFormatter: .isoDateFormatter)
func runWithResponseStatus(_ request: URLRequest, checkStatusCode statusCode: Int = 200, queue: DispatchQueue = .main, retries: Int = 0) -> AnyPublisher<(data: Data, response: URLResponse), Error> {
var cancellable = Set<AnyCancellable>()
return URLSession.shared.dataTaskPublisher(for: request)
.retry(retries)
.tryMap { output in
if let response = output.response as? HTTPURLResponse, response.statusCode != statusCode {
switch response.statusCode {
case 401:
try refresh(decodingType: AccessData.self)
.sink { completion in
switch completion {
case .finished:
break
case .failure(let error):
print("\(error.localizedDescription)")
}
} receiveValue: { newAccessToken in
auth.setAccessToken(to: newAccessToken.token)
}
.store(in: &cancellable)
case 400:
throw ResourceError.internalServerError("General.error.general")
default:
throw ResourceError.httpStatus(response.statusCode)
}
}
return output
}
.receive(on: queue)
.eraseToAnyPublisher()
}
private func refresh<DecodingType>(checkStatusCode statusCode: Int = 200, queue: DispatchQueue = .main, decodingType: DecodingType.Type) throws -> AnyPublisher<DecodingType, Error> where DecodingType: Decodable {
// prepare all properties ...
return URLSession.shared.dataTaskPublisher(for: refreshRequest)
.tryMap { output in
if let response = output.response as? HTTPURLResponse, response.statusCode != statusCode {
switch response.statusCode {
case 401:
auth.loggedOut()
case 400:
throw ResourceError.internalServerError("General.error.general")
default:
auth.loggedOut()
throw ResourceError.httpStatus(response.statusCode)
}
}
return output.data
}
.decode(type: DecodingType.self, decoder: jsonDecoder)
.receive(on: queue)
.eraseToAnyPublisher()
}
}
答案 0 :(得分:0)
我相信你可以catch
或replaceError
。尝试阅读:https://www.donnywals.com/catch-vs-replaceerror-in-combine/