Question

我正在为 discord bot 编写一些代码，当我在执行取消静音和静音时，我试图让它发送消息，如果它们已经静音或未静音，但我无法正确处理任何帮助都会非常有用有帮助。谢谢

module.exports = {
    name: 'unmute',
    description: "This unmutes a member",
    execute(message, args){
        
            if (message.member.hasPermission('MUTE_MEMBERS')) {
                
                if (member.roles.cache.has(mainRoleId)){
                return message.channel.send('Provided member isnt muted');

                }else{

                const target = message.mentions.users.first();
        if(target){
            let mainRole = message.guild.roles.cache.find(role => role.name === 'Verified');
            let muteRole = message.guild.roles.cache.find(role => role.name === 'MUTED');

            let memberTarget= message.guild.members.cache.get(target.id);

            memberTarget.roles.remove(muteRole.id);
            memberTarget.roles.add(mainRole.id);
            message.channel.send(`<@${memberTarget.user.id}> has been unmuted`);
        } else{
            message.channel.send('Cant find that member!');
        }         
        }else { 
             message.reply('you do not have permissions to use this command');
            }
        }
    }

https://i.stack.imgur.com/CAhNe.png

Answer 1

 if (member.roles.cache.has(mainRoleId)){
                return message.channel.send('Provided member isn't muted.');

mainRoleId 和成员被静音之间有什么关系？如果我正确理解你的推理，你应该在 let muteRole = message.guild.roles.cache.find(role => role.name === 'MUTED'); 语句的开头声明 if，然后使用

 if (!member.roles.cache.has(muteRoleId)){
                return message.channel.send('Provided member isn't muted.');

const target = message.mentions.users.first();

一旦有人忘记传递参数，您的机器人就会崩溃。记得在命令的开头做一些万无一失的检查，就像这样（假设你想在 args 中传递未静音的人，这是一个必需的参数）：

if (!args[0]) return message.reply(`not enough arguments!`);
if (message.mentions.users.first() == undefined) return message.reply(`user not found!`);

现在，至于标题中的问题，鉴于我的回复并拥有函数 if (member.roles.cache.has(muteRoleId))，您应该可以自己弄清楚。

你好，我正在为 discord bot 做一些代码，当我在做取消静音和静音时，我试图让它发送消息

1 个答案: