Question

我有以下代码以编程方式创建UIWebView并在其上创建UIButton以关闭它。创建没问题，但问题是我无法回复创建的UIWebView来关闭按钮！

UIWebView *webView = [[UIWebView alloc] initWithFrame:CGRectMake(0, 0, 320, 480)];
NSURL *url = [NSURL URLWithString:@"http://www.google.com"];
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
[webView loadRequest:requestObj];
[self.view addSubview:webView];

UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
[button addTarget:self 
           action:@selector(aMethod:)
 forControlEvents:UIControlEventTouchDown];
[button setTitle:@"Close" forState:UIControlStateNormal];
button.frame = CGRectMake(80, 210, 160, 40);
[button addTarget:self action:@selector(close:) forControlEvents:UIControlEventTouchUpInside];
[webView addSubview:button];

- (IBAction)close:(id)sender {
????
}

提前感谢您的帮助：）

Answer 1

在ViewController.m中

UIWebView *webView = [[UIWebView alloc] initWithFrame:CGRectMake(0, 0, 320, 480)];

// tag will be used to get this webview later
webView.tag=55;
NSURL *url = [NSURL URLWithString:@"http://www.google.com"];
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
[webView loadRequest:requestObj];
[self.view addSubview:webView];

UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
[button addTarget:self 
           action:@selector(close:)
 forControlEvents:UIControlEventTouchDown];
[button setTitle:@"Close" forState:UIControlStateNormal];
button.frame = CGRectMake(80, 210, 160, 40);
[button addTarget:self action:@selector(close:) forControlEvents:UIControlEventTouchUpInside];
[webView addSubview:button];





- (IBAction)close:(id)sender {

    [[self.view viewWithTag:55] removeFromSuperview];


}

Answer 2

将您的webView保持为UIViewController的ivar。

现在您将它作为方法的局部变量，因此您无法在该方法之外引用它。相反，在.h文件的界面部分声明它，您将能够从所有类方法中访问它。

不要忘记在dealloc方法中释放它！

Answer 3

网页视图是按钮的超级视图，因此你应该能够像这样获得它，

UIWebView * webView = [(UIButton *)sender superview];

现在你可以removeFromSuperview或其他东西让它消失。

修改

- (IBAction)close:(id)sender { UIWebView * webView = [(UIButton *)sender superview]; [webView removeFromSuperview]; }

Answer 4

-(BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {

    NSLog(@"%@",request.URL.absoluteString);
    NSString *absoluteUrl = [[request URL] absoluteString];
    if ([absoluteUrl isEqualToString:@"https://google.com/login?"]) {
        NSLog(@"move to another view or close the web view");
        [portfolioWebView removeFromSuperview];

        return NO;
    }

    return YES;
}

如何关闭以编程方式创建的UIWebView？

4 个答案: