Question

我遇到的问题是我要解决的问题。

我已经设定了一项任务，其中大多数都会执行以下操作;

1）在数组中的每个数字上，打印出（在无序列表中）每个数字的数组值及其相关描述。

代码是执行此任务，如下所示;

var numbers = [
  '1',
  '2',
  '3',
  '4',
  '5',
  '6'
],

description = {
  'One': 'Number one',
  'Two': 'Number two',
  'Three': 'Number three',
  'Four': 'Number four',
  'Five': 'Number five',
  'Six': 'Number six'
};

有没有人知道如何使用某种循环来解决这个问题？

如果你还可以在评论中向我解释，告诉我发生的事情会很棒。

亲切的问候，

乙

Answer 1


for(var prop in description) {

    alert(prop+"::"+description[prop]);
}

这将帮助您迭代描述对象。您可以修改它以匹配数组值。

Answer 2

您可以指定一个对象数组，每个对象包含一个与该对象的索引值对应的描述：

// assign an array of objects
// numbers[3] for example contains {name: 'Three', description: 'Number three'}
var numbers = [
  {name: 'Zero',  description: 'Zip!'},
  {name: 'One',   description: 'Number one'},
  {name: 'Two',   description: 'Number two'},
  {name: 'Three', description: 'Number three'},
  {name: 'Four',  description: 'Number four'},
  {name: 'Five',  description: 'Number five'},
  {name: 'Six',   description: 'Number six'}
],
// a results container
result = [];
// iterate through the numbers array and push a string
// string containing index, name and description to
// result
for (var i=0;i<numbers.length,i=i+1){
   result.push(i+': name = '+numbers[i].name+
               ', description = '+numbers[i].description);
}
// show the result, joining the result array into a string,
// separated by a line break '\n'
alert(result.join('\n'));

/* alerts:
 0: name = Zero, description = Zip!
 1: name = One, description = Number one
 2: name = Two, description = Number two
 3: name = Three, description = Number three
 4: name = Four, description = Number four
 5: name = Five, description = Number five
 6: name = Six, description = Number six
*/

初学者Javascript问题....迭代数组

2 个答案: