Question

我想从以下XML中读取ContactId和Notes。我尝试使用Openxml并声明命名空间，但我无法获得预期的结果。请求您提供解决方案。

<ArrayOfContact xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Contact>
<ContactId xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">100</ContactId>
<Notes xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">Test1</Notes>
</Contact>
<Contact>
<ContactId xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">101</ContactId>
<Notes xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">Test2</Notes>
</Contact>
</ArrayOfContact>

Answer 1

OPENXML函数是SQL Server 2000的遗留XML支持，我使用xml数据类型中引入的更新的XML方法。

DECLARE @x xml;
SET @x = '<ArrayOfContact xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Contact>
<ContactId xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">100</ContactId>
<Notes xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">Test1</Notes>
</Contact>
<Contact>
<ContactId xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">101</ContactId>
<Notes xmlns="http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData">Test2</Notes>
</Contact>
</ArrayOfContact>';

WITH XMLNAMESPACES ('http://www.thomsonreuters.com/2011/02/25/CMS/CmsService/ContactData' AS cms)
SELECT
    contact.value('cms:ContactId[1]', 'int') ContactId, 
    contact.value('cms:Notes[1]', 'nvarchar(MAX)') Notes 
    FROM @x.nodes('/ArrayOfContact/Contact') AS contacts(contact);

在SQL Server 2008中读取XML

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