我的javascript代码不会继续从jqGrid中删除我的数据

Question

只想询问我的javascript代码。我有一个函数，将删除和编辑我的jqgrid中的数据。但每次我运行我的代码时，如果我没有在代码的某些部分发出警报，它将不会删除和编辑。为什么会这样？如何让我的程序在没有警报的情况下运行？

以下是我的删除功能：

function woodSpeDelData(){

var selected = $("#tblWoodSpe").jqGrid('getGridParam', 'selrow');  
  var woodID='';
  var woodDesc='';
  var codeFlag = 0;
  var par_ams = {
    "SessionID": $.cookie("SessionID"),
    "dataType": "data"
  };
    //this part here will get the id of the data since my id was hidden in my jqgrid
  $.ajax({
    type: 'GET',
    url: 'processjson.php?' + $.param({path:'getData/woodSpecie',json:JSON.stringify(par_ams)}),
    dataType: primeSettings.ajaxDataType,
    success: function(data) {
      if ('error' in data)
      {
        showMessage('ERROR: ' + data["error"]["msg"]);
      }
      else{  
        $.each(data['result']['main']['rowdata'], function(rowIndex, rowDataValue) {
          $.each(rowDataValue, function(columnIndex, rowArrayValue) {
            var fldName = data['result']['main']['metadata']['fields'][columnIndex].name;
            if (fldName == 'wood_specie_id'){
              woodID = rowArrayValue; 
            }                
            if (fldName == 'wood_specie_desc'){   
              woodDesc = rowArrayValue; 
              alert($('#editWoodSpeDesc').val() +' '+ woodDesc); //program will not delete without this
              if(selected == woodDesc){
                codeFlag =1;
                alert(woodID);    //program will not delete without this
              };        
            }                   
          }); 
          if (codeFlag == 1){
            return false;
          }
        }); 
        if (codeFlag == 1){
          return false;
        }
      }
    }            
  });
  alert('program will not proceed without this alert');
  if (codeFlag == 1) {
    var datas = {
      "SessionID": $.cookie("SessionID"),
      "operation": "delete",
      "wood_specie_id": woodID
    };
    alert(woodID);
    alert(JSON.stringify(datas));
    $.ajax({
      type: 'GET',
      url: 'processjson.php?' + $.param({path:'delete/woodSpecie',json:JSON.stringify(datas)}),
      dataType: primeSettings.ajaxDataType,
      success: function(data) {
        if ('error' in data)
        {
          showMessage('ERROR: ' + data["error"]["msg"]);
        }
        else{
          $('#tblWoodSpe').trigger('reloadGrid'); 
        }
      }
    });
  }
} 

修改

我发出警报的主要目的只是为了知道我的代码是否真的得到了描述的正确ID，如果真的会得到我的代码流...但后来我意识到它真的不会用它