Question

目前我正在使用Google Maps JavaScript API V3过滤地图结果。我有两个javascript下拉菜单。选择一个下拉选项值后，地图会过滤到该设置。因此，如果我选择业务类型“社会服务”，则地图将仅显示此类业务。第二个过滤器用于不同的主题。因此，如果选择了第二个下拉菜单，它将过滤到此选项值。问题是，当选择第二个或第一个时，它在过滤时忽略另一个。例如，我希望用户能够从第一个菜单中过滤“社交服务”，从第二个菜单中过滤“机会”。这将显示符合这两个标准的位置。现在用户只能选择其中一个。

以下是页面：

LTI Maps

以下是代码：

    <html> 
<head> 
<meta name="viewport" content="initial-scale=1.0, user-scalable=no" /> 
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/> 
<!DOCTYPE html>
<title>Met Sacramento Internship Map</title> 

<!-- Style --> 
<style> 
  body { font-family: Arial, sans-serif; }
  #map_canvas { height: 500px; width:600px; }
</style> 

<script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script> 
<script type="text/javascript"> 
    var tableid = 567682;
    var layer = new google.maps.FusionTablesLayer(567682); 

  function initialize() {
    var latlng = new google.maps.LatLng(38.59970036588819, -121.541748046875);
    var myOptions = {
      zoom: 8,
      center: latlng,
      mapTypeId: google.maps.MapTypeId.ROADMAP
    };
    var map = new google.maps.Map(document.getElementById("map_canvas"),
        myOptions);
          layer.setMap(map);
  }
    //Change the query based on the user's selection
function interestMap(interest) {
 layer.setQuery("SELECT Address, 'Interest Area' FROM " + tableid + " WHERE 'Interest Area' CONTAINS '" + interest + "'"); 
}
function statusMap(status) {
 layer.setQuery("SELECT Address, 'Status' FROM " + tableid + " WHERE 'Status' CONTAINS '" + status + "'"); 
}
</script>

 </script> 

</head> 
<body onload="initialize();">  
  Internship Status <select onchange="interestMap(this.value);"> 
    <option value="">Interest Areas</option>
<option value="Aerospace">Aerospace</option>
<option value="Animals">Animals</option>
<option value="Architecture">Architecture</option>
<option value="Art/Music/Theatre">Art/Music/Theatre</option>
<option value="Athletics and Martial Arts">Athletics</option>
<option value="Automotive and Transportation">Automotive</option>
<option value="Business">Business</option>
<option value="Community Development">Community Development</option>
<option value="Computers">Computers</option>
<option value="Cosmetology">Cosmetology</option>
<option value="Culinary">Culinary</option>
<option value="Education">Education</option>
<option value="Government and Politics">Politics</option>
<option value="Health Science">Health Science</option>
<option value="Hospitality/Tourism/Event Planning">Event Planning</option>
<option value="Law and Public Safety">Law and Public Safety</option>
<option value="Marketing">Marketing</option>
<option value="Media and Information Technology">Media</option>
<option value="Photography">Photography</option>
<option value="Science and Technology">Science and Technology
</option>
<option value="Social Services">Social Services</option>
  </select>
   Status <select onchange="statusMap(this.value);"> 
    <option value="">Status</option>
<option value="BEING PURSUED">Being Pursued</option>
<option value="HAS INTERN">Has Intern</option>
<option value="NOT TAKING">Not Taking</option>
<option value="OPPORTUNITY">Opportunity</option>
<option value="OVER 18">Over 18</option>
<option value="POTENTIAL?">Potential</option>
<option value="SEE NOTES">See Notes</option>


  </select>
  <div id="map_canvas"></div>

</body> 
</html>

非常感谢你的帮助。

Answer 1

我没有使用2个不同的过滤功能，而是根据下拉列表中的值创建一个过滤器。

这样的事情：

function filterResults(){
    var interest = document.getElementById('ddl-interest').value;
    var status = document.getElementById('ddl-status').value;

    layer.setQuery("SELECT Address, 'Interest Area' FROM " + tableid + 
    " WHERE 'Interest Area' CONTAINS '" + interest + "' AND 'Status' CONTAINS '" + status + "'");
}

然后你显然需要给你的下拉列表ids'ddl-interest'和'ddl-status'并在onchange事件上调用'filterResults'方法。

Javascript地图过滤器问题

1 个答案: