Question

我将多个表格连接在一起以获取项目的最新交易日期、股票代码、股票名称、UOM 代码、汇率、UOM 价格、当前余额。

问题是获得最高费率的 UOM 价格 很容易，但是如果我想根据最高费率获得 UOM 单价怎么办？是通过做这个公式UOM Price / Rate = Price Per Unit

在我看来，我想这样做：

如果一件商品有多个 UOM 代码，请检查是否有多个费率。
如果是，则执行公式并将值设为最低费率，因为它是商品的每单位价格。
如果否，则无需执行公式。

这是我的代码

SELECT *
FROM(
    SELECT 
        TransactionDate,    -- from StockTransactions Table
        DocumentCode,       -- from StockTransactions Table
        StockCode,          -- from Stocks Table
        StockName,          -- from Stocks Table
        UOMCode,            -- from UOMs Table      
        Rate,               -- from UOMs Table  
        st.UOMPriceExcLandingCost as UOMPrice, -- from StockTransactions Table  
        FORMAT(CurrentBalance, 'N4') AS CurrentBalance, --from stocks table
        ROW_NUMBER() OVER(PARTITION BY StockCode, UOMCode ORDER BY TransactionDate DESC) RN -- sort from latest to oldest stock transactions based on stockcode and UOMCode
    FROM UOMs us
        LEFT JOIN Stocks s ON s.Id = us.StockId -- join Stocks Table
        LEFT JOIN StockTransactions st ON st.StockId = us.StockId   -- join StockTransactions Table
        LEFT JOIN StockPurchasePriceHistory spph on spph.Stock = us.StockId
    WHERE 
        st.TransactionDate BETWEEN '2000-01-01' AND GETDATE()   --get result from specific transaction date in StockTransations Table
        AND st.Qty > 0
        AND st.DocumentCode NOT LIKE 'SA%'  --get all documentcode except documentcode that start with SA in StockTransations Table 
        OR st.DocumentCode  LIKE 'SA1503%'  --get all documentcode that start with SA1503 in StockTransations Table
        AND st.DocumentCode NOT LIKE 'CN%'  --get all documentcode except documentcode that start with CN in StockTransations Table     
    GROUP BY 
        --group columns that might have multple records with different stock transactions date
        TransactionDate,
        DocumentCode,
        StockCode,
        StockName,
        UOMCode,
        Rate,
        st.UOMPriceExcLandingCost,
        CurrentBalance
) StockInquiry
WHERE 
    RN = 1  -- get latest date in stockpurchasepricehistory table
    AND StockCode = 'WRC3MM'  -- for checking purpose only
ORDER BY StockCode ASC -- sort result by stockcode in ascending order

这是我的输出

这是数据库的示例：SQLFiddle

这是使用 ApexSQL = Google Drive 的数据库提取示例

输出应该是：

如果是 METER 那么它应该是 230 / 305 = 0.7540 Price Per Unit
如果 ROLL/305 那么它应该是 230

如果您现在查看 UOM 价格，它会以最高的价格获得最高的价格。即使商品具有不同的UOM 代码，也可以解决这个问题吗？

Answer 1

我认为您需要修改对 [StockTransactions] 的连接，以便在连接逻辑中包含 UOMid PLUS 您还可以将 row_number() 计算包含在子查询中，以便您只连接到该行的最新行表：

/* modified */
    SELECT 
        TransactionDate,    -- from StockTransactions Table
        DocumentCode,       -- from StockTransactions Table
        StockCode,          -- from Stocks Table
        StockName,          -- from Stocks Table
        UOMCode,            -- from UOMs Table      
        Rate,               -- from UOMs Table  
        st.UOMPriceExcLandingCost as UOMPrice, -- from StockTransactions Table
        FORMAT(CurrentBalance, 'N4') AS CurrentBalance, --from stocks table
        st.RN
    FROM UOMs us
        INNER JOIN Stocks s ON s.Id = us.StockId    -- join Stocks Table
        INNER JOIN (
                select *
                    , row_number() over(partition by StockId, UOMid order by TransactionDate DESC) as rn
                from StockTransactions
                ) st ON st.StockId = us.StockId AND st.UOMid = us.id AND rn = 1
    WHERE 
        st.TransactionDate BETWEEN '2000-01-01' AND GETDATE()   --get result from specific transaction date in StockTransations Table
        AND st.Qty > 0
        AND (st.DocumentCode NOT LIKE 'SA%' --get all documentcode except documentcode that start with SA in StockTransations Table 
          OR st.DocumentCode  LIKE 'SA1503%')   --get all documentcode that start with SA1503 in StockTransations Table
        AND st.DocumentCode NOT LIKE 'CN%'  --get all documentcode except documentcode that start with CN in StockTransations Table     
;

结果：

+-----------------+--------------+-----------+--------------------------------+-----------+------+----------+----------------+----+
| TransactionDate | DocumentCode | StockCode |           StockName            |  UOMCode  | Rate | UOMPrice | CurrentBalance | RN |
+-----------------+--------------+-----------+--------------------------------+-----------+------+----------+----------------+----+
| 2015-03-01      | SA1503/388   | WRC3MM    | WIRE ROPE GI C/W COVER 3MMX5MM | METER     |    1 |     0.75 |        22.3000 |  1 |
| 2016-05-14      | BIL1605/065  | WRC3MM    | WIRE ROPE GI C/W COVER 3MMX5MM | ROLL/305M |  305 |      230 |        22.3000 |  1 |
+-----------------+--------------+-----------+--------------------------------+-----------+------+----------+----------------+----+

demo

另外，我认为你需要在 where 子句中使用括号来控制 OR，但我不知道我是否正确地引入了这些。

Answer 2

感谢 Paul Maxwell 的解决方案，我已经解决了我的问题

这是最终的代码，我不确定这是否是正确的方法，但它有效

SELECT
    DocDate,
    DocCode,
    StockCode,
    FORMAT((Price / us.Rate), 'N4') AS PricePerUnit,
    UOMCode AS LastPurchasePriceUOM,
    FORMAT(Price, 'N4') AS LastPurchasePrice,
    FORMAT(CurrentBalance, 'N4') AS Balance,
    st.RN
FROM StockPurchasePriceHistory spph
    INNER JOIN Stocks s ON spph.Stock = s.Id    
    INNER JOIN (
        SELECT 
            Id, 
            Rate, 
            UOMCode 
        FROM UOMs 
        WHERE 
        UOMs.Description IS NULL
    ) us ON spph.UOM = us.Id
    INNER JOIN (
        SELECT
            StockId,
            UOMId,
            TransactionDate, 
            DocumentCode, 
            ROW_NUMBER() OVER(PARTITION BY StockId, UOMId ORDER BY TransactionDate DESC) AS RN 
        FROM StockTransactions
    ) st ON st.StockId = spph.Stock AND st.UOMId = us.Id AND RN = 1
WHERE 
    st.TransactionDate BETWEEN '2000-01-01' AND GETDATE()
    AND (st.DocumentCode NOT LIKE 'SA%' OR st.DocumentCode LIKE 'SA1503%')
    AND st.DocumentCode NOT LIKE 'CN%'
ORDER BY StockCode ASC

此处示例：SQL Fiddle

输出是这样的：

<头>

文档日期	文档代码	股票代码	PricePerUnit	最后购买价格UOM	最后购买价格	平衡	注册护士
2016-05-13	BIL1605/065	WRC3MM	0.7541	滚动/305M	230.0000	22.3000	1

如何根据最高费率的商品价格获得每单位价格

2 个答案: