Question

所以，我是 MIPS 的新手，正在为二次公式编写代码......我认为我做的一切都是正确的，但我的程序总是给出错误的答案，有时它会因 PC 0x004000f8 的异常而中止

请如果有人能告诉我我哪里出错了以及是否有任何其他差异在我的代码中，请指导。谢谢！

    .data
promptfora: .asciiz "Enter Value of a: "
promptforb: .asciiz "Enter Value of b: "
promptforc: .asciiz "Enter Value of c: "
finalansdisplay: .asciiz "root is:"
answer: .word 0



.text
.globl main
main:


#b in t1


li $v0, 4
la $a0, promptforb
syscall

li $v0, 5
syscall
move $t1, $v0



#a in t2


li $v0, 4
la $a0, promptfora
syscall

li $v0, 5
syscall
move $t2, $v0



#value of c in t3

li $v0, 4
la $a0, promptforc
syscall

li $v0, 5
syscall
move $t3, $v0



move $a0, $t1                          # pass arg's to function
jal power
move $t4, $v0                          #b^2

mul $t5,$t2,$t3                       # ac in t5

mul $t5,$t5,4

sub $a0,$t4,$t5                       # b^2 - 4ac

jal iSqrt


mul $t1,$t1,-1                   #- * b

add $t6,$t1,$v0                    # - b + sqrt(b^2 - 4ac)
 

mul $t2,$t2,2                      #2a 

div $t7, $t6,$t2                 #final root 


li $v0, 4
la $a0, finalansdisplay  
syscall

move $a0, $t6
li $v0, 1        #display final answer
syscall


li $v0, 10
syscall

.end main


#Function to square b

.globl power    
.ent power

power:

li $v0, 1

mul $v0, $a0, $a0

jr $ra
.end power


#Function for root


.globl iSqrt
.ent iSqrt
iSqrt:

move $v0, $a0 # $v0 = x = N

li $t0, 0 # counter
sqrLoop:

div $t1, $a0, $v0 # N/x

add $v0, $t1, $v0 # x + N/x

div $v0, $v0, 2 # (x + N/x)/2

add $t0, $t0, 1

blt $t0, 20, sqrLoop
jr $ra

.end iSqrt

Answer 1

试试这个，并为另一个根稍微改变这个你必须改变一些东西，你如何做这是你的测试

.data
prompt: .asciiz "Enter number 1: "
prompt2: .asciiz "Enter number 2: "
prompt3: .asciiz "Enter number 3: "
newline: .asciiz "\n"
answer: .word 0
sqanswer:  .word 0
 
.text
.globl main
.ent main

main:
li $v0, 4
la $a0, prompt  
syscall

li $v0, 5
syscall
move $t1, $v0   

li $v0, 4
la $a0, prompt2   
syscall

li $v0, 5
syscall
move $t2, $v0     

li $v0, 4
la $a0, prompt3  
syscall

li $v0, 5
syscall
move $t3, $v0    

addi $a0, $t2, 0

#lw $a0, prompt
#lw $a1, prompt2
jal power

sw $v0, answer
lw $s0, answer 

li $t4, 4
mul $t5, $t1, $t3   
mul $t5, $t5, $t4   
li $t6, 2
mul $t7, $t6, $t1
sub $a1, $s0, $t5   

jal iSqrt

sw $v1, sqanswer
lw $s3, sqanswer 


li $s1, -1
mul $s1, $t2, $s1   
add $s2, $s1, $s3   
div $s3, $s2, $t7

move $a0, $s3
la $v0, 1
syscall 

li $v0, 10
syscall

.end main


.globl power
.ent power

power:

mul $v0, $a0, $a0

jr $ra

.end power

.globl iSqrt
.ent iSqrt

iSqrt:

move $v1, $a1   
li $t0, 0   

sqrLoop:

div $t8, $a1, $v1
add $v1, $t8, $v1
div $v1, $v1, 2 
add $t0, $t0, 1
blt $t0, 20, sqrLoop

jr $ra

.end iSqrt

Answer 2

试试这个代码！

.数据

prompt: .asciiz "Enter valie for a :"
prompt2: .asciiz "Enter value for b:"
prompt3: .asciiz "Enter value for c:"

.text .globl 主

主要：里 $v0,4 la $a0, 提示系统调用

li $v0,5
syscall
move $t1, $v0

li $v0,4
la $a0,prompt2
syscall

li $v0,5
syscall
move $t2, $v0

li $v0,4
la $a0,prompt3
syscall

li $v0,5
syscall
move $t3, $v0    

move $a0,$t2
jal power
move $t0, $v0

mul $t3,$t3,4
mul $t3, $t3,$t1
sub $t0, $t0, $t3

move $a0,$t0
jal sqrt
move $t0, $v0

sub $t0, $t0,$t2
mul $t1, $t1, 2
div $t0, $t0, $t1

li $v0,1
move $a0,$t0
syscall

li $v0, 10
syscall
.end main

功率： mul $v0, $a0, $a0 jr $ra

.结束电源方格：移动 $v0, $a0 li $t5,0

sqrtloop: div $t6, $a0, $v0 添加 $v0、$t6、$v0 div $v0 $v0,2 添加 $t5,$t5,1 blt $t5, 20, sqrtloop jr $ra .end sqrt

我在这个 MIPS 代码中哪里出错了？

2 个答案: