是否有一种简单的方法可以将 SoapRequest 捕获到
DetailSoapFaultDefinitionExceptionResolver extends SoapFaultMappingExceptionResolver
????
进入方法
protected void customizeFault(Object endpoint, Exception ex, org.springframework.ws.soap.SoapFault fault){
...... method code
}
在父类中:
public abstract class AbstractSoapFaultDefinitionExceptionResolver extends AbstractEndpointExceptionResolver
请求在方法中: protected final boolean resolveExceptionInternal(MessageContext messageContext, Object endpoint, Exception ex)
进入 MessageContext 对象。