在教程之后使用spring安全性似乎很容易,但是当我尝试使用这个应用程序时,我可以让它工作(我必须承认我还没写过)。
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现在在一些优秀人员的帮助下,我终于得到了要求用户验证自己的应用程序,但现在我遇到了一个新问题:当我尝试使用下面列出的一个用户访问该应用程序时( applicationContext-security.xml ),我收到此消息:
这是web.xml
代码:
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext-security.xml</param-value>
</context-param>
<welcome-file-list>
<welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>
<error-page>
<error-code>403</error-code>
<location>/sinacceso.jsp</location>
</error-page>
</web-app>
context.xml:
<?xml version="1.0" encoding="UTF-8"?>
<Context antiJARLocking="true" path="/Test01"/>
调度-servlet.xml中:
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">
<beans>
<!-- GENERALES -->
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.tiles2.TilesView" />
</bean>
<bean id="tilesConfigurer"
class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean name="/index.htm" class="paginas.index"/>
<bean name="secure/villancicos.htm" class="paginas.villancicos"/>
<bean name="secure/administracion.htm" class="paginas.administracion"/>
</beans>
的applicationContext-security.xml文件:
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<http>
<intercept-url pattern="/index.htm" filters="none" />
<intercept-url pattern="/secure/administracion.htm" access="ROLE_SUPERVISOR" />
<intercept-url pattern="/secure/**" access="ROLE_USER" />
<form-login />
<anonymous />
<http-basic />
<logout logout-success-url="/index.htm" />
</http>
<authentication-manager alias="myAuthenticationManager">
<authentication-provider>
<password-encoder hash="md5"/>
<user-service>
<user name="rod" password="a564de63c2d0da68cf47586ee05984d7" authorities="ROLE_SUPERVISOR, ROLE_USER, ROLE_TELLER" />
<user name="dianne" password="65d15fe9156f9c4bbffd98085992a44e" authorities="ROLE_USER,ROLE_TELLER" />
<user name="scott" password="2b58af6dddbd072ed27ffc86725d7d3a" authorities="ROLE_USER" />
<user name="peter" password="22b5c9accc6e1ba628cedc63a72d57f8" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
此应用程序目前正在使用带有spring-security-2.0.4的spring 2.5(与我一直关注的教程中的版本相同)。
答案 0 :(得分:0)
您是否尝试过该错误建议并为您的身份验证管理器添加了别名属性?类似的东西:
<authentication-manager alias="myAuthenticationManager">
<authentication-provider>
...