如何在Rails 3中使用Mongoid嵌入式资源创建嵌套表单?

时间:2011-07-13 21:24:31

标签: ruby-on-rails ruby-on-rails-3 mongodb mongoid ruby-on-rails-3.1

我有一个Recipe模型,其中嵌入了成分,使用Mongoid。

class Recipe
  include Mongoid::Document
  include Mongoid::Timestamps

  field :title, :type => String
  embeds_many :ingredients

  accepts_nested_attributes_for :ingredients, :reject_if => lambda { |a| a[:title].blank? }, :allow_destroy => true

  validates :title, :presence => true
end

class Ingredient
  include Mongoid::Document
  field :name, :type => String
  field :quantity, :type => String

  embedded_in :recipe, :inverse_of => :ingredients
end

我希望能够同时创建一个新食谱,以及该食谱的相关成分,但我很难理解我将如何做到这一点。这就是我到目前为止所做的:

_form.html.erb - 在食谱视图中使用

<%= form_for @recipe do |f| %>  
...
  <li>Title: <%= f.text_field :title %></li>

  <% f.fields_for :ingredients do |builder| %>
    <%= render "ingredient_fields", :f => builder %>
  <% end %>
...
<%= f.submit %>

_ingredient_fields.html.erb

<%= f.text_field :name %>

配方控制器

def new
  @recipe = Recipe.new
  @ingredient = @recipe.ingredients.build
end

def create
  @recipe = Recipe.new(params[:recipe])


  if @recipe.save
    redirect_to @recipe, notice: 'Recipe was successfully created.'
  else
    render action: "new"
  end
end

成分控制器

def new
  @recipe = Recipe.find(params[:recipe_id])
  @ingredient = @recipe.ingredients.build
end

def create
  @recipe = Recipe.find(params[:recipe_id]) 
  @ingredient = @recipe.ingredients.build(params[:ingredient]) 
  # if @recipe.save 
end

这使得新成分形成,但成分没有领域。谁能给我任何关于我做错的指示?

2 个答案:

答案 0 :(得分:8)

当您显示嵌套表单时,请尝试使用(注意等于):

<%= f.fields_for

而不仅仅是

<% f.fields_for

请参阅此类似question

答案 1 :(得分:2)

我最近遇到了一个非常类似的问题。我在Github上的Mongoid问题跟踪器上发现了类似的问题非常有帮助:

https://github.com/mongoid/mongoid/issues/1468#issuecomment-6898898

瘦线就是那条线

= f.fields_for :ingredients do |builder|

应如下所示:

= f.fields_for @recipe.ingredients do |builder|