Question

我正在制作一个单位转换器，用户可以在其中自由选择他想要的单位并进行转换我正在制作温度单位（摄氏度、开尔文和华氏度）的转换器，但我偶然发现了一个错误，即使我试图删除它们，标签也会被覆盖

这里是处理这个的函数：

# Phase 2
def phase_2():

    # The Subphases
    # Temp
    def temprature():

        mega.forget()

        heading = Label(root, text="Temprature", padx=40, pady=15, relief=SUNKEN)
        heading.pack()

        frameps = LabelFrame(root)
        frameps.pack(padx=10, pady=10)

        def conversion():

            # Answer Box
            answer = LabelFrame(frameps, padx=10)
            answer.grid(row=3, column=4, columnspan=1, padx=20, pady=20)

            empty = Label(answer, text="Value")
            empty.grid(row=0, column=0)

            # C functions
            def C_F():                 
                empty = Label(answer, text=f"{(int(val.get()) * (9 / 5)) + 32}°F")
                empty.grid(row=0, column=0)

            def C_K():
                empty = Label(answer, text=f"{int(val.get()) + 273.15}°K")
                empty.grid(row=0, column=0)

            def C_C():
                empty = Label(answer, text=f"{int(val.get())}°C")
                empty.grid(row=0, column=0)

            # F functions
            def F_C():
                empty = Label(answer, text=f"{(int(val.get()) - 32) * 5/9}°C")
                empty.grid(row=0, column=0)

            def F_K():
                empty = Label(answer, text=f"{(int(val.get()) - 32) * 5/9 + 273.15}°K")
                empty.grid(row=0, column=0)

            def F_F():
                empty = Label(answer, text=f"{int(val.get())}°F")
                empty.grid(row=0, column=0)

            # K functions
            def K_F():
                empty = Label(answer, text=f"{(int(val.get()) - 273.15) * 9/5 + 32}°F")
                empty.grid(row=0, column=0)

            def K_C():
                empty = Label(answer, text=f"{int(val.get()) - 273.15}°C")
                empty.grid(row=0, column=0)

            def K_K():
                empty = Label(answer, text=f"{int(val.get())}°K")
                empty.grid(row=0, column=0)


            # C probs
            if unit.get() == "C" and u.get() == "F":
                answer.forget()
                C_F()
            if unit.get() == "C" and u.get() == "K":
                answer.forget()
                C_K()
            if unit.get() == "C" and u.get() == "C":
                answer.forget()
                C_C()
            
            # F probs
            if unit.get() == "F" and u.get() == "C":
                answer.forget()
                F_C()
            if unit.get() == "F" and u.get() == "K":
                answer.forget()
                F_K()
            if unit.get() == "F" and u.get() == "F":
                answer.forget()
                F_F()
            
            # K probs
            if unit.get() == "K" and u.get() == "F":
                answer.forget()
                K_F()
            if unit.get() == "K" and u.get() == "C":
                answer.forget()
                K_C()
            if unit.get() == "K" and u.get() == "K":
                answer.forget()
                K_K()

如您所见，我一直在尝试“answer.forget”，以便忘记标签，然后每次使用转换器按钮时都会重写，但是，却发生了这种情况：

Answer 1

总体思路是构建一次布局并根据需要更改值，如下所示：

import tkinter as tk


class MainApplication(tk.Frame):
    def __init__(self, parent, *args, **kwargs):
        tk.Frame.__init__(self, parent, *args, **kwargs)
        self.parent = parent

        self.count = 0

        self.label = tk.Label(self, text="Click the button!")
        self.label.pack()

        self.some_button = tk.Button(self, text="Click", command=self.some)
        self.some_button.pack()

        self.close_button = tk.Button(self, text="Close", command=self.quit)
        self.close_button.pack()

    def some(self):
        self.count += 1
        self.label["text"] = f"You clicked {self.count} times."


if __name__ == "__main__":
    root = tk.Tk()
    MainApplication(root).pack(side="top", fill="both", expand=True)
    root.mainloop()

因此，当您点击 Convert 按钮时，您应该在您的应用中调用一个函数，并在其中读取您需要的值和设置，并使用新结果更新标签内的文本。< /p>

This 回答解释了如何使用 OOP 方法构建您的应用程序，我认为随着您的应用程序的发展，这非常有用。

干杯！

标签被覆盖，如何删除

1 个答案: