我正在编写一个脚本来打印与给定字符串匹配的单元格的列号和行号,然后将其输出到文本文件。单个 awk
命令在终端中运行良好,我已经解决了其他语法问题,但输出的 .txt 仍然为空。我想我在将 shell 变量传递给 awk
时遇到了问题。
#!/bin/bash
echo Literal or regex string to find:
read string
echo File path to find string match in:
read filename
echo "Matches for $string were found in the following cells:" > results.txt
for string in filename
do
awk -v awkvar="$string" -F"," '{for(i=1;i<=NF;i++){if ($i ~ /awkvar/){print i}}}' $filename >> results.txt | echo -e "\n" >> results.txt
awk -v awkvar="$string" '/awkvar/{print NR}' $filename >> results.txt | echo -e "\n" >> results.txt
done
问题已解决
我已将脚本重写如下:
#!/bin/bash
# Prompt for input: 1. enter file name or path that you want searched; 2. enter the literal or regex string
echo File name or path to find matches in:
read file
echo Literal or regex string to find:
read string
# Define variable and test if any matches are to be found; if not, notification is sent to terminal, but if matches exist, their row numbers (as summary rows) and individual column numbers will be output to a .txt file in the home directory. NB: you need to escape minus symbol with brackets, [-], so that it's not confused with an invalid grep option!
matchesFound=$(cat $file | grep -E -c "$string")
if [ $matchesFound -eq 0 ];
then
echo "No matches exist."
else
printf "Summary Row No: \n`awk -v awkvar="$string" '$0 ~ awkvar{print NR}' $file`" > results_for_$string.txt
printf "\nInstance Column No: \n`awk -v awkvar="$string" -F"," '{for(i=1;i<=NF;i++){if ($i ~ awkvar){print i}}}' $file`" >> results_for_$string.txt
fi
答案 0 :(得分:5)
您不能在正则表达式检查模式中使用 awk
变量,请尝试以下方法。您可以使用 index
的 awk
函数并检查条件是否尝试不使用 /../
方式。
awk -v awkvar="$string" -F"," '{for(i=1;i<=NF;i++){if ($i ~ awkvar){print i}}}' $filename >> results.txt | echo -e "\n" >> results.txt
awk -v awkvar="$string" 'index($0,awkvar){print NR}' $filename >> results.txt | echo -e "\n" >> results.txt
此答案仅处理 OP 根据问题显示的 awk
代码,以修复它。