我正在使用fixture来为我的symfony项目生成数据,但由于某种原因,以下错误不断被抛出:
无法执行INSERT语句。 [包装:SQLSTATE [23000]: 完整性约束违规:1452无法添加或更新子行: 外键约束失败(
meeting
。meeting_attendance
, 约束meeting_attendance_FK_1
外键(meeting_id
) 参考meeting_meetings
(id
))]
我正在寻找错误发生的原因,我正在使用Symfony 1.4,带有propel和MySQL数据库。
会议架构和考勤架构如下所示,http://pastebin.com/HZhaqWSN
的完整副本 meeting_meetings:
id: ~
owner_id: { type: integer, foreignTable: sf_guard_user_profile, foreignReference: user_id, required: true }
group_id: { type: integer, foreignTable: meeting_groups, foreignReference: id }
name: { type: varchar, required: true, default: Meeting }
completed: { type: boolean, required: true, default: 0 }
location: { type: varchar, required: true, default: Unknown }
start: { type: integer, required: true }
length: { type: integer, required: true, default: 60 }
created_at: ~
updated_at: ~
meeting_attendance:
id: ~
meeting_id: { type: integer, foreignTable: meeting_meetings, foreignReference: id, required: true }
user_id: { type: integer, foreignTable: sf_guard_user_profile, foreignReference: user_id, required: true }
invited: { type: boolean, required: true, default: 0 }
attending: { type: boolean, required: true, default: 0 }
apolgies: { type: boolean, required: true, default: 0 }
attended: { type: boolean, required: true, default: 0 }
apolgies_comment: { type: varchar(255) }
03_meetings.yml如下
MeetingMeetings:
PezMeeting:
owner_id: Pezmc
completed: 0
location: Awesome Room
start: 1310059022
length: 60
和09_attendance.yml如下:
MeetingAttendance:
MeetingAttendance1:
meeting_id: PezMeeting
user_id: Pezmc
invited: 1
attending: 1
apolgies: 0
attended: 0
apolgies_comment: None
我的两个灯具都是使用PHP随机生成的,但我已将它们更改为上面的内容以尝试找到此错误!
我认为我一定忽略了一些简单的事情,但我一直试图调试这个超过一个小时,我的智慧结束了!
有谁知道导致此错误的原因或解决方法?
非常感谢你的时间,
编辑:有人建议将所有内容放在一个文件中,我已经完成了这个并使用php运行该文件(以确切了解推送的内容)。它仍然会出现同样的错误:
MeetingMeetings:
PezMeeting:
owner_id: Pezmc
completed: 0
location: Awesome Room
start: 1310059022
length: 60
MeetingItems:
Item1:
Value: VfH0qXxGV4Ylb ZtRm DKkDE9dTzlWR z Nm TnNhxVPvZO eOn IM5 v ETOl v 4 xsA7HexNwzB YDvz I uay Sjm3rbAu iaiZIPGv l0oNSFCG To
MeetingAgendas:
Agenda1:
MeetingId: PezMeeting
ItemId: Item1
MeetingActions:
Action1:
ItemId: Item1
MeetingId: PezMeeting
Due: 1310705295
Start: 1310358321
Completed: 1
MeetingAttendance:
MeetingAttendance1:
meeting_id: PezMeeting
user_id: Pezmc
invited: 1
attending: 1
apolgies: 0
attended: 0
仍在:
Unable to execute INSERT statement. [wrapped: SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`meeting`.`meeting_agendas`, CONSTRAINT `meeting_agendas_FK_1` FOREIGN KEY (`meeting_id`) REFERENCES `meeting_meetings` (`id`))]
编辑2:表的生成SQL在这里:http://pastebin.com/XQmM3k7S(下面的一些表)DROP TABLE IF EXISTS meeting_meetings
;
CREATE TABLE `meeting_meetings`
(
`id` INTEGER NOT NULL AUTO_INCREMENT,
`owner_id` INTEGER NOT NULL,
`group_id` INTEGER,
`name` VARCHAR(255) default 'Meeting' NOT NULL,
`completed` TINYINT default 0 NOT NULL,
`location` VARCHAR(255) default 'Unknown' NOT NULL,
`start` INTEGER NOT NULL,
`length` INTEGER default 60 NOT NULL,
`created_at` DATETIME,
`updated_at` DATETIME,
PRIMARY KEY (`id`),
INDEX `meeting_meetings_FI_1` (`owner_id`),
CONSTRAINT `meeting_meetings_FK_1`
FOREIGN KEY (`owner_id`)
REFERENCES `sf_guard_user_profile` (`user_id`),
INDEX `meeting_meetings_FI_2` (`group_id`),
CONSTRAINT `meeting_meetings_FK_2`
FOREIGN KEY (`group_id`)
REFERENCES `meeting_groups` (`id`)
)Type=InnoDB;
答案 0 :(得分:1)
此灯具必须位于同一文本文档中以帮助保存!
答案 1 :(得分:0)
此灯具必须位于同一个文件中。我的意思是来自03_meetings.yml和09_attendance.yml的灯具
我希望这会有用。
答案 2 :(得分:0)
在config / ProjectConfiguration.class.php中尝试此操作。然后在数据加载后将其注释掉。
class ProjectConfiguration extends sfProjectConfiguration
{
public function setup()
{
// ...
}
public function configureDoctrine(Doctrine_Manager $manager)
{
$manager->setAttribute(Doctrine_Core::ATTR_QUOTE_IDENTIFIER, true);
}
}