Question

 [
    {
        "hotelid": [
            {
                "hotelid": "1",
                "name": "aaa",
                "code": "111",
                "price": "111"
            },            
            {
                "hotelid": "2",
                "name": "bbb",
                "code": "112",
                "price": "211"
            },
            {
                "hotelid": "4",
                "name": "ccc",
                "code": "42",
                "price": "411"
            }

...

我有这个JSON，我怎么能在android中解析它？我试过了，但我只是弄错了。

代码：

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    mycontext=this;

    examineJSONFile();
}

class Result
{
  List<Hotel> hotel; // name matches name in JSON

  @Override
  public String toString() {return hotel.toString();}
}


class Hotel
{
  String code;          // name matches name in JSON
  String name;          // name matches name in JSON
  String hotelid;       // name matches name in JSON

  @Override
  public String toString()
  {
    return String.format("hotelid:{code=%s, name=%s, hotelid=%s}", code, name, hotelid);  
  }
}


void examineJSONFile()    {

    InputStream is = this.getResources().openRawResource(R.raw.promo);
    String s;
    try {
        s = HttpConnect.streamToString(is);

        ObjectMapper mapper = new ObjectMapper();
        mapper.setVisibilityChecker(mapper.getVisibilityChecker().withFieldVisibility(Visibility.ANY));

        Result[] results = mapper.readValue(s, Result[].class);
        Result result = results[0];

        Log.e("res", result.toString()+"");


    } catch (Exception e) {
        Log.e("err", e+"");
    }


}

错误/错误（23124）：org.codehaus.jackson.map.JsonMappingException：可以不反序列化类com.android.asd.asdStart $ Result（类型非静态成员类）作为Bean

Answer 1

我试图解析那个JSON字符串，我有一个解决方案，请尝试这个：

String parse = "[{\"hotelid\":[{\"hotelid\":\"1\",\"name\":\"aaa\",\"code\":\"111\",\"price\":\"111\"},{\"hotelid\":\"2\",\"name\":\"bbb\",\"code\":\"112\",\"price\":\"211\"},{\"hotelid\":\"4\",\"name\":\"ccc\",\"code\":\"42\",\"price\":\"411\"}]}]";
            try {
                JSONArray menuObject = new JSONArray(parse);
                for(int i=0;i<menuObject.length();i++){
                    String hotel =    menuObject.getJSONObject(i).getString("hotelid").toString();
                    System.out.println("hotel="+hotel);
                    JSONArray menuObject1 = new JSONArray(hotel);
                    for(int j=0; j<menuObject1.length();j++){
                        String hotelid =    menuObject1.getJSONObject(j).getString("hotelid").toString();
                        System.out.println("hotelid=="+hotelid);

                        String name =    menuObject1.getJSONObject(j).getString("name").toString();
                        System.out.println("name=="+name);

                        String code =    menuObject1.getJSONObject(j).getString("code").toString();
                        System.out.println("code=="+code);

                        String price =    menuObject1.getJSONObject(j).getString("price").toString();
                        System.out.println("price=="+price);

                    }
                }

            } catch (JSONException e) {
                e.printStackTrace();
            }

Answer 2

这个问题被问过这么多次。

使用com.google.gson包。它与org.json包（json.jar）的99％相似。

下次你应该谷歌。

Answer 3

以下是使用Jackson作为Java-to / from-JSON库的示例。 Jackson是快速，功能最丰富的Java / JSON API之一。

我猜测了实际目标JSON结构是什么。

import java.util.List;

import org.codehaus.jackson.annotate.JsonAutoDetect.Visibility;
import org.codehaus.jackson.map.ObjectMapper;

public class Foo
{
  public static void main(String[] args) throws Exception
  {
    // input:
    // [
    //   {
    //     "hotel": [
    //       {"id":"52472","name":"africa","hotel":"asd"},
    //       {"id":"52471","name":"europe","hotel":"asd2"},
    //       {"id":"52470","name":"europe","hotel":"asd3"}
    //     ]
    //   }
    // ]
    String input = "[{\"hotel\":[{\"id\":\"52472\",\"name\":\"africa\",\"hotel\":\"asd\"},{\"id\":\"52471\",\"name\":\"europe\",\"hotel\":\"asd2\"},{\"id\":\"52470\",\"name\":\"europe\",\"hotel\":\"asd3\"}]}]";

    ObjectMapper mapper = new ObjectMapper();
    // configure Jackson to access non-public fields
    mapper.setVisibilityChecker(mapper.getVisibilityChecker().withFieldVisibility(Visibility.ANY));

    Result[] results = mapper.readValue(input, Result[].class);
    Result result = results[0];
    System.out.println(result);
  }
}

class Result
{
  List<Hotel> hotel; // name matches name in JSON

  @Override
  public String toString() {return hotel.toString();}
}

class Hotel
{
  String id; // name matches name in JSON
  String name; // name matches name in JSON
  String hotel; // name matches name in JSON

  @Override
  public String toString()
  {
    return String.format("Hotel:{id=%s, name=%s, hotel=%s}", id, name, hotel);  
  }
}

Answer 4

使课程结果和酒店静止。解析器无法创建非静态的内部类的实例

Answer 5

此JSON无效。你错过了关闭]支架。您可以查看您的JSON here

Android JSON解析这个，怎么样？

5 个答案: