我正在使用 php 中的 post 方法从 python 脚本中获取数据并将该数据存储在数据库中。
PHP 脚本:
<?php
if (isset($_POST['sign'])) {
$sign = $_POST['sign'];
$msg = $_POST['msg'];
echo $sign . " " . $msg ;
$sql1 = "INSERT INTO data1 (message, sign)
VALUES ('$msg','$sign')";
if ($conn->query($sql1) === TRUE) {
echo "New record created successfully";
}
else {
echo "Error: " . $sql1 . "<br>" . $conn->error;
}
}
else {
echo "";
}
$sql2 = "SELECT message FROM data1 WHERE id= (SELECT max(id) FROM data1) AND sign= '".$sign."'";
$result = $conn->query($sql2);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "message: " . $row["message"];
$c= escapeshellcmd('python new.py' .$row["message"] );
echo "<br>";
}
}
else {
echo "0 results";
}
?>
数据完美地存储在数据库中,但在执行读取查询后,它给出了“未定义变量:符号”的错误 如果有人对此有任何想法,请分享谢谢。
答案 0 :(得分:0)
您的代码仅在 $sign
为真时(当有带有键 if (isset($_POST['sign']))
的 POST 数据)时才定义变量 sign
,但是您在内部使用了 $sign
变量第二个 SQL 查询,位于 if
语句之外。
$sql2 = "SELECT message FROM data1 WHERE id= (SELECT max(id) FROM data1) AND sign= '".$sign."'";`
为了修复未定义的变量错误,您应该将这段代码移到 if
主体内部。
<?php
if (isset($_POST['sign'])) {
$sign = $_POST['sign'];
$msg = $_POST['msg'];
echo $sign . " " . $msg ;
$sql1 = "INSERT INTO data1 (message, sign)
VALUES ('$msg','$sign')";
if ($conn->query($sql1) === TRUE) {
echo "New record created successfully";
}
else {
echo "Error: " . $sql1 . "<br>" . $conn->error;
}
$sql2 = "SELECT message FROM data1 WHERE id= (SELECT max(id) FROM data1) AND sign= '".$sign."'";
$result = $conn->query($sql2);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "message: " . $row["message"];
$c= escapeshellcmd('python new.py' .$row["message"] );
echo "<br>";
}
}
else {
echo "0 results";
}
}
else {
echo "";
}