Question

我是python的新手，我不得不在python中编写我的第一个任务。我保证在完成这项工作后我将从内到外学习它，但我现在需要你的帮助。

我的代码目前看起来像这样：

comSocket.send("\r")
sleep(1)
comSocket.send("\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

comSocket.send("\r\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

errorLog是另一种方法。我想通过创建一个新方法来重写此代码，以便我可以传递message，引用socket，然后return我从套接字收到的内容。

任何帮助？

谢谢：）

Answer 1

猜测你想要的是什么：

def send_and_receive(message, socket):
    socket.send(message)
    return socket.recv(256) # number is timeout

然后将try:except:放在此方法的调用上。

Answer 2

一个简单的解决方案是

def socketCom(comSocket, length, message, time):
    comSocket.send(message)
    comSocket.settimeout(8)
    if (time != 0):
        sleep(time)
    try:
        rawData = comSocket.recv(length)
    except socket.timeout:
        errorLog("[COM. ERROR] Station took too long to reply. \n")
        comSocket.shutdown(1)
        comSocket.close()
        sys.exit(0)

    return rawData

Answer 3

您应该执行一个类来管理您的错误，并且该类需要扩展您用于comSocket实例的类，在您放置errorLog函数的类中。像这样：

class ComunicationSocket(socket):
    def errorLog(self, message):
        # in this case, self it's an instance of your object comSocket, 
        # therefore your "reference"
        # place the content of errorLog function
        return True # Here you return what you received from socket

现在只用它来实现它的实例化ComunicationSocket：

comSocket = ComunicationSocket()
try:
    comSocket.recv(256)
except socket.timeout:
    # Uses the instance of comSocket to log the error
    comSocket.errorLog("[COM. ERROR] Station took too long to reply. \n")
    comSocket.shutdown(1)
    comSocket.close()
    sys.exit(0)

希望有帮助，你没有发布你的功能错误日志的内容，所以我把评论放在你应该放的地方。这是一种做事方式。希望有所帮助。

Python：通过引用传递套接字

3 个答案: