Question

我有这个简单的django模型，由传感器和特定传感器的值组成。每个日射强度计的值的数量很高（> 30k）。是否有可能在特定日期前对PyranometerValues进行分页，或者将一个分页器应用于管理员内联视图？

class Pyranometer(models.Model):
     name = models.CharField(max_length=75)                                                                             

class PyranometerValues(models.Model):                                                                                 
    timestamp = models.DateTimeField()
    value = models.DecimalField(max_digits=10,decimal_places=6)                                                        
    sensor = models.ForeignKey('Pyranometer')

Answer 1

如果有人要求这样做，我发现this comment问题的a django-suit中的分页TabularInline子类的实现很好（虽然被描述为“非常hacky”）。

对于Django 1.6，它需要模板更改并继承此PaginationInline类：

from django.contrib import admin
from django.contrib.admin.views.main import ChangeList
from django.core.paginator import EmptyPage, InvalidPage, Paginator

class InlineChangeList(object):
    can_show_all = True
    multi_page = True
    get_query_string = ChangeList.__dict__['get_query_string']

    def __init__(self, request, page_num, paginator):
        self.show_all = 'all' in request.GET
        self.page_num = page_num
        self.paginator = paginator
        self.result_count = paginator.count
        self.params = dict(request.GET.items())


class PaginationInline(admin.TabularInline):
    template = 'admin/edit_inline/tabular_paginated.html'
    per_page = 20

    def get_formset(self, request, obj=None, **kwargs):
        formset_class = super(PaginationInline, self).get_formset(
            request, obj, **kwargs)
        class PaginationFormSet(formset_class):
            def __init__(self, *args, **kwargs):
                super(PaginationFormSet, self).__init__(*args, **kwargs)

                qs = self.queryset
                paginator = Paginator(qs, self.per_page)
                try:
                    page_num = int(request.GET.get('p', '0'))
                except ValueError:
                    page_num = 0

                try:
                    page = paginator.page(page_num + 1)
                except (EmptyPage, InvalidPage):
                    page = paginator.page(paginator.num_pages)

                self.cl = InlineChangeList(request, page_num, paginator)
                self.paginator = paginator

                if self.cl.show_all:
                    self._queryset = qs
                else:
                    self._queryset = page.object_list

        PaginationFormSet.per_page = self.per_page
        return PaginationFormSet

Answer 2

您是否检查过raw_id_fields属性？我想你可能会发现它很有用。

Answer 3

由于django-admin主要是模板问题（只需要将模板重新定义为某些django-admin-tools部分），我有一个想法。

Django的分页模块，如linaro-django-pagination或endless-pagination，它们提供模板标签，以便在可迭代的情况下分页。

如果您可以找到负责显示内联模型的模板，您可以将其复制到项目中，然后尝试向其添加{％load pagination_tags％}并对内联进行分页。

我没有对它进行过测试，也没有仔细考虑过，但除了验证之外，我看不出它是如何失败的。试试并告诉我们。

Answer 4

对于任何版本的Django ，请按照以下步骤操作：

访问此文件：python3.7/site-packages/django/contrib/admin/templates/admin/edit_inline/tabular.html在您的app/templates/admin/edit_inline/anyname.html中复制它

在</table>和</fieldset>标记之间添加 anyname.html ：

   <style>
    .dark {
      /*background-color: #417690;*/
      background-color: #FFFFFF;
      border: none;
      color: #666;
      padding: 5px 10px;
      text-align: center;
      text-decoration: none;
      display: inline-block;
      font-size: 12px;
      margin: 4px 2px;
      cursor: pointer;
    }
    .light {
      background-color: #008CBA;
      border: none;
      color: white;
      padding: 5px 10px;
      text-align: center;
      text-decoration: none;
      display: inline-block;
      font-size: 12px;
      margin: 4px 2px;
      cursor: pointer;
    }

  </style>
   <div>
   {% with inline_admin_formset.formset.page as page_obj %}
    <p class="paginator">
      {% if page_obj.previous_page_number > 1 %}
        <a href="?page={{ page_obj.previous_page_number|add:'-1' }}">{% trans 'previous' %}</a>
      {% endif %}

      {% if page_obj.number|add:"-5" > 0 %}
        <a href="?page=0">1</a>
      {% endif %}

      {% if page_obj.number|add:"-5" > 1 %}
        <span>&hellip;</span>
      {% endif %}

      {% for page_num in page_obj.paginator.page_range %}
        {% if page_obj.number == page_num %}
          <span class="dark">{{ page_num|add:"-1" }}</span>
        {% else %}
          {% if page_num > page_obj.number|add:"-5" and page_num < page_obj.number|add:"5" %}
            <a class="light" style="color:white" href="?page={{ page_num|add:'-1' }}">{{ page_num|add:"-1" }}</a>
          {% endif %}
        {% endif %}
      {% endfor %}

      {% if page_obj.number|add:"5" < page_obj.paginator.num_pages %}
        <span>&hellip;</span>
      {% endif %}

      {% if page_obj.number|add:"4" < page_obj.paginator.num_pages %}
        <a href="?page={{ page_obj.paginator.num_pages }}">{{ page_obj.paginator.num_pages }}</a>
      {% endif %}

      {% if page_obj.next_page_number < page_obj.paginator.num_pages|add:'1' %}
        <a href="?page={{ page_obj.next_page_number|add:'-1' }}">{% trans 'next' %}</a>
      {% endif %}
      <span class='dark'>{{ page_obj.paginator.count }} Queries</span>
    </p>
  {% endwith %}
  </div>

2。转到您的 admin.py 文件：

from django.contrib.admin.views.main import ChangeList
from django.core.paginator import EmptyPage, InvalidPage, Paginator

class InlineChangeList(object):
    can_show_all = True
    multi_page = True
    get_query_string = ChangeList.__dict__['get_query_string']

    def __init__(self, request, page_num, paginator):
        self.show_all = 'all' in request.GET
        self.page_num = page_num
        self.paginator = paginator
        self.result_count = paginator.count
        self.params = dict(request.GET.items())


class MyInline(admin.TabularInline):
    per_page = 10
    template = 'admin/edit_inline/anyname.html'
    model = Mymodel
    extra = 0
    can_delete = False

    def get_formset(self, request, obj=None, **kwargs):
        formset_class = super(MyInline, self).get_formset(
            request, obj, **kwargs)
        class PaginationFormSet(formset_class):
            def __init__(self, *args, **kwargs):
                super(PaginationFormSet, self).__init__(*args, **kwargs)

                qs = self.queryset
                paginator = Paginator(qs, self.per_page)
                try:
                    page_num = int(request.GET.get('page', ['0'])[0])
                except ValueError:
                    page_num = 0

                try:
                    page = paginator.page(page_num + 1)
                except (EmptyPage, InvalidPage):
                    page = paginator.page(paginator.num_pages)

                self.page = page
                self.cl = InlineChangeList(request, page_num, paginator)
                self.paginator = paginator

                if self.cl.show_all:
                    self._queryset = qs
                else:
                    self._queryset = page.object_list

        PaginationFormSet.per_page = self.per_page
        return PaginationFormSet

Answer 5

好吧，也许动态生成的过滤器会有所帮助：

https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_filter

此外，管理员有一个很好的GET类型查询，如：

本地主机：8000 /管理/ pyranometervalues /值= 10.0

您可以将日期指定为：

管理员/ pyranometervalues / timestamp_ 年= 2011＆安培;时间戳 _month = 10安培; timestamp__day = 13

依旧...不幸的是我不知道在admin中进行此查询的简短方法。有任何想法吗？：）

编辑：这只是为了缩小查询范围，与分页无关;）

用于django admin中的内联模型的Paginator

5 个答案: