如何在我的上传表格中输入内容,此代码无效
这是我的项目数组:
[Project] => Array ( [name] => Testproject [description] => TestDescription [Upload] => Array ( [0] => Array ( [name] => testlink1 [Type] => link )
[1] => Array
(
[name] => testlink2
[Type] => link
)
[2] => Array
(
[name] => testlink3
[Type] => link
)
)
)
我写过
foreach($this->data['Project']['Upload'] as $key=>$value)
{
$this->data['Upload'][$key]['project_id'] = $this->Project->id;
$this->data['Upload'][$key]['name'] = $value['name'];
$this->data['Upload'][$key]['type'] = $value['Type'];
$this->data['Upload'][$key]['created'] = date("Y-m-d H:i:s");
$this->data['Upload'][$key]['modified'] = date("Y-m-d H:i:s");
$this->Project->Upload->save($this->data['Upload'][$key]);
}
答案 0 :(得分:1)
你不需要foreach。只要保持真诚,你的关联是正确的:
/app/models/project.php
var $hasMany = array('Upload');
/app/models/upload.php
var $belongsTo = array('Project');
如果您拥有如上所述的数据阵列,则可以使用$this->Project->saveAll($this->data)
一次保存所有内容。
查看手册以获取有关saveAll的更多信息以及如何保存相关数据:Saving related model data