我有php脚本将给它的值发送到MSSQL数据库。它大约70%的时间工作(应该有~100条记录,我会看到~70条)。没有模式,我可以看到。我不是在寻找有关我已经拥有的日志的帮助;我需要知道我应该在哪里找到错误。 php很简单,使用mssql_query,mssql_num_rows和mssql_fetch_array。 php.ini中的超时没有从默认的60s更改,虽然我刚刚将其设置为240s(如果这修复了所有内容,我将更新帖子)。一旦调用脚本,我就无法返回任何内容;每个响应,无论是否有错误,都必须相同。我可以以某种方式记录mssql_query函数的详细信息吗?或者我可以收听的SQL服务器是否有响应?我已阅读手册,并没有看到这样的事情。任何帮助,将不胜感激!我需要尽快照顾。
编辑 -
我无法运行mssql_showlastmessage,因为我不能返回任何东西,因为事情会破坏。以下是整个代码。
<?php
//request xml cdr from switchvox
error_reporting(E_ALL);
//include switchvox libraries
require_once("SwitchvoxRequest.php");
//define sql connection stuff
$db_host = "dbhost";
$db_user = "dbuser";
$db_pass = "dbsecret";
$db = "db";
$table_sr = "tblsr";
$table_cd = "tblcmrd";
$link = mssql_connect($db_host, $db_user, $db_pass);
$err = "";
//make sure we can connect
if (!$link || !mssql_select_db($db, $link))
{
die("<response></response>");
}
//define pbx connection stuff
$sv_host = "pbx";
$sv_user = "user";
$sv_pass = "secret";
//get the extension from the pbx and format it
$ext = $_GET['ext'];
$ext2 = $_GET['ext2'];
$jobid = $_GET['jobid'];
$et = $_GET['et'];
if(!$ext2)
{
$ext = substr($ext,-4,4);
}
if(strlen($ext) > 4)
{
if(strlen($ext2) > 4)
{
die("<response></response>");
}
$ext = $ext2;
}
//query the sr table to find the account ID of the extension we are referencing
$acid_sql = "SELECT * FROM $table_sr WHERE ext=$ext";
$acid_res = mssql_query($acid_sql);
$acida = mssql_fetch_array($acid_res, MSSQL_BOTH);
$acid = $acida['pbx_accountid'];
if (!$acid_res)
{
die("<response></response>");
}
//make sure there is a salesrep for the extension making the call
if (!$acid)
{
die("<response></response>");
}
//get and format the time and date as YYYY-MM-DD
$date = date('Y') . "-" . date('m') . "-" . date('d');
//format the time as HH:MM:SS
$time = date('H') . ":" . date('i') . ":" . date('s');
//create a new request
$req = new SwitchvoxRequest($sv_host, $sv_user, $sv_pass);
$reqpar = array
(
'account_ids' => array
(
'account_id' => array
(
$acid
)
),
'start_date' => array
(
$date . " " . "00:00:00"
),
'end_date' => array
(
$date . " " . $time
),
'sort_field' => array
(
),
'sort_order' => array
(
'DESC'
)
);
$res = $req -> send("switchvox.callLogs.search", $reqpar);
$result = $res->getResult();
$calls = $result['calls']['total_items'];
//check that there were calls to/from this account today
if(!$calls)
{
die("<response></response>");
}
$latest = $result['calls']['call']['0'];
$callid = $latest['id'];
//check to see if the call has already been logged
$id_sql = "SELECT * FROM $table_cd WHERE callID='$callid'";
$id_res = mssql_query($id_sql);
$exid = mssql_fetch_array($id_res, MSSQL_ASSOC);
if (!$id_res)
{
die("<response></response>");
}
if($exid['callID'])
{
die("<response></response>");
}
//define variables to be sent to the table
$from = $latest['from_number'];
$to = $latest['to_number'];
$durat = $latest['talk_duration'];
$start = $latest['start_time'];
$callid = $latest['id'];
$calltype = $latest['origination'];
//check the length of the cid/ext strings and swap if needed
if (strlen($from) > strlen($to))
{
$extension = $to;
$phonenumber = $from;
}
else
{
$extension = $from;
$phonenumber = $to;
}
//insert the data into the table
$fi_sql = "INSERT INTO $table_cd (extension, phonenumber, calldatetime, duration, callID, calltype) VALUES ($extension, $phonenumber, '$start', '$durat', '$callid', '$calltype')";
$fi_res = mssql_query($fi_sql);
if (!$fi_res)
{
die("<response></response>");
}
$sv_res = "<response></response>";
echo $sv_res;
?>
我意识到这对sql注入是开放的。没关系。
编辑 -
我查看了数据库中的日志;没有错误,我希望有什么时候插入数据,甚至没有任何表明它尝试过。我将看一些将消息记录到syslog或者某些东西的东西。欢迎提出建议。
答案 0 :(得分:0)
通常,您可以在MySQL上自由执行此操作
EXPLAIN SELECT ...
获取SELECT语句的描述。此功能基本上解释了MySQL的查询分析器如何查看您的查询以及如何执行查询。例如,EXPLAIN
描述,如果MySQL即将执行昂贵的表扫描,或者可能使用索引,如果是,则使用哪一个。
你确定,MySQL导致了这个问题吗?或者PHP可能会出问题?
您是否在每次查询后检查mysql_error()?
$ ext可能不是数字吗?在这种情况下,$ ext应该被引用(抱歉,不喜欢字符串中的变量替换):
$acid_sql = "SELECT * FROM " . $table_sr . " WHERE ext='" . $ext . "'";
由于您返回XML并且此例程的客户端表现良好,为什么不在响应中插入新元素,如下所示:
<response>
... other elements ...
<sysInfo>
Failed to perform...
</sysInfo>
</response>
行为良好的XML客户端应该只读取已知元素,从而跳过其他元素。添加这样的逻辑返回代码总是有用的。
PS:虽然上面的代码可能只是一个示例,但请注意,它可以被 sql-injections 攻击。