Question

所以我一直在为学校项目开发 Spring Boot 应用程序，但我无法运行它，因为当我尝试保存在存储库中时，我收到以下错误。我尝试了很多事情，比如改变关系类型，添加级联，但似乎没有任何效果。下面是 2 个类和 main 的代码以及错误

package com.site.anime.model;
import lombok.AllArgsConstructor;
import lombok.Data;
import lombok.NoArgsConstructor;
import org.hibernate.annotations.Fetch;

import javax.persistence.*;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

@Entity
@NoArgsConstructor
@AllArgsConstructor
@Data
public class Show {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;


    private String name;
    private String image;



    private Integer no_episodes;
    private String description;
    private Double overall_score;

    @ManyToMany
    private List<Caracter> caracters;

    @OneToMany
    private List<Review> reviews;

    @ManyToMany
    private List<Category> categories;

}

package com.site.anime.model;
import lombok.AllArgsConstructor;
import lombok.Data;
import lombok.NoArgsConstructor;

import javax.persistence.*;
import java.util.List;

@Entity
@NoArgsConstructor
@AllArgsConstructor
@Data
public class Caracter {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    private String name;
    private String image;


    private String description;

    @ManyToMany
    private List<Show> shows;
}

package com.site.anime;
import com.site.anime.model.*;
import com.site.anime.repository.*;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.annotation.Bean;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;

import java.util.HashMap;
import java.util.LinkedList;
import java.util.List;

@EnableJpaRepositories
@SpringBootApplication
public class AnimeApplication {

    public static void main(String[] args) {
        SpringApplication.run(AnimeApplication.class, args);
    }

    @Bean
    CommandLineRunner init(RepositoryShow repositoryShow, RepositoryCategory repositoryCategory,
                           RepositoryCaracter repositoryCaracter, RepositoryUser repositoryUser,
                           RepositorySuperUser repositorySuperUser){
        return args -> {

            List<Show> shows=new LinkedList<>();
            Caracter caracter=new Caracter(null,"rusu","","",null);

            List<Caracter> caracters=new LinkedList<>();
            caracters.add(caracter);

            Profile profile=new Profile();
            Utilizator user=new Utilizator(null,"","","",profile,null);
            //Review review=new Review(null,user,"",0);
            Review review=new Review(null,null,"",0);
            List<Review> reviews=new LinkedList<>();
            reviews.add(review);

            user.setReviews(reviews);
            Show show=new Show(null,"ReZero Season 1","",25,"",0.0,null,reviews,null);

            shows.add(show);

            caracter.setShows(shows);

            show.setCaracters(caracters);
//


            //repositoryShow.save(show);
            repositoryCaracter.save(caracter);
            //repositoryUser.save(user);





        };
    }
}

和错误

2021-03-11 14:11:02.765  INFO 10248 --- [           main] o.h.e.t.j.p.i.JtaPlatformInitiator       : HHH000490: Using JtaPlatform implementation: [org.hibernate.engine.transaction.jta.platform.internal.NoJtaPlatform]
2021-03-11 14:11:02.771  INFO 10248 --- [           main] j.LocalContainerEntityManagerFactoryBean : Initialized JPA EntityManagerFactory for persistence unit 'default'
2021-03-11 14:11:03.007  WARN 10248 --- [           main] JpaBaseConfiguration$JpaWebConfiguration : spring.jpa.open-in-view is enabled by default. Therefore, database queries may be performed during view rendering. Explicitly configure spring.jpa.open-in-view to disable this warning
2021-03-11 14:11:03.065  INFO 10248 --- [           main] o.s.s.concurrent.ThreadPoolTaskExecutor  : Initializing ExecutorService 'applicationTaskExecutor'
2021-03-11 14:11:03.193  INFO 10248 --- [           main] o.s.b.w.embedded.tomcat.TomcatWebServer  : Tomcat started on port(s): 8080 (http) with context path ''
2021-03-11 14:11:03.198  INFO 10248 --- [           main] com.site.anime.AnimeApplication          : Started AnimeApplication in 2.922 seconds (JVM running for 3.566)
2021-03-11 14:11:03.245  WARN 10248 --- [           main] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 1064, SQLState: 42000
2021-03-11 14:11:03.245 ERROR 10248 --- [           main] o.h.engine.jdbc.spi.SqlExceptionHelper   : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'show (description, image, name, no_episodes, overall_score, id) values ('', '', ' at line 1
2021-03-11 14:11:03.252  INFO 10248 --- [           main] ConditionEvaluationReportLoggingListener : 

Error starting ApplicationContext. To display the conditions report re-run your application with 'debug' enabled.
2021-03-11 14:11:03.263 ERROR 10248 --- [           main] o.s.boot.SpringApplication               : Application run failed
``

Answer 1

SHOW 是 MySql 的 keyword（以及 NAME 和 DESCRIPTION），因此您应该使用 SQL quoted identifier，如下所示：

@Entity
@Table(name = "`show`")
public class Show {

  // ...

  @Column(name = "`name`")
  private String name;

  @Column(name = "`description`")
  private String description;

}

Answer 2

我解决了这个问题对于任何想知道的人，我的一个类叫做 Show，而 sql 有一个保留字叫做 show

我在尝试运行 Spring Boot 应用程序时遇到问题

2 个答案: