Question

<?php
$feedURL = 'http://########.tumblr.com/api/read/';

$xml = simplexml_load_file($feedURL);
// $posts = $xml->xpath("/tumblr/posts/post");
foreach($xml->posts->post as $post){
$post= $xml->posts->post->{'photo-url'};
}   
echo "<pre>";
print_r($post);
echo "</pre>";

?>

这是我制作的剧本。我只能获取第一篇文章，但我希望显示所有帖子，并且不显示帖子图片。

Answer 1

试试这个：

foreach($xml->posts->post as $post){
    $post_urls[] = (string) $post->{'photo-url'};
} 

echo "<pre>";
print_r($post_urls);
echo "</pre>";

评论更新：

foreach($xml->posts->post as $post){
   $posts[] = (array)$post->attributes() + (array) $post->children();
} 

echo "<pre>";
print_r($posts);
echo "</pre>";

更新2：

foreach($xml->posts->post as $post){
    $img = (string) $post->{'photo-url'};
    echo '<img src="' . $img . '" />';
}

Answer 2

我已经使用

了

foreach($xml->posts->post as $post){
    $img = (string) $post->{'photo-url'};
    echo '<img src="' . $img . '" />';
}

但是它只显示了几张图片而不是所有的想法？

使用tumblr API，后期图像不会显示

2 个答案: