1 namespace Uploader
2 {
3 using System;
4 using System.IO;
5 using System.ServiceModel;
6 using System.ServiceModel.Description;
7 using System.ServiceModel.Web;
8 using System.Drawing;
9 using System.Drawing.Imaging;
10 using System.Net;
11 using System.Xml;
12
13 [ServiceContract(Namespace = "http://Uploader")]
14 public interface IUploaderService
15 {
16 [OperationContract, WebInvoke(Method = "POST",UriTemplate = "File/{fileName}")]
17 bool UploadFile(string fileName, Stream fileContents);
18 }
19
20 [ServiceBehavior(InstanceContextMode = InstanceContextMode.PerCall)]
21 public class UploaderService : IUploaderService
22 {
23 public bool UploadFile(string fileName, Stream fileContents)
24 {
25 return true;
26 }
27 }
28
29 class Program
30 {
31 static void Main()
32 {
33 var host = new
34 ServiceHost(typeof (UploaderService),
35 new Uri("http://localhost:8080/Uploader"));
36 host.AddServiceEndpoint("Uploader.IUploaderService",
37 new WebHttpBinding(), "").Behaviors.Add(new WebHttpBehavior());
38 try
39 {
40 host.Open();
41 Console.WriteLine(host.BaseAddresses[0].AbsoluteUri + " running.");
42 Console.WriteLine();
43 var uri = "http://localhost:8080/Uploader/file.jpg";
44 var req = WebRequest.Create(uri) as HttpWebRequest;
45 if (req != null)
46 {
47 req.Method = "POST";
48 req.ContentType = "image/jpeg";
49 var reqStream = req.GetRequestStream();
50
51 var imageStream = new MemoryStream();
52 using (var i = Image.FromFile(@"c:\photo.jpg"))
53 i.Save(imageStream, ImageFormat.Jpeg);
54
55 var imageArray = imageStream.ToArray();
56 reqStream.Write(imageArray, 0, imageArray.Length);
57 reqStream.Close();
58 var resp = (HttpWebResponse)req.GetResponse();
59 var r = new XmlTextReader(resp.GetResponseStream());
60 if (r.Read())
61 {
62 Console.WriteLine(r.ReadString());
63 }
64 }
65 Console.WriteLine("Press <ENTER> to quit.");
66 Console.ReadLine();
67 }
68 catch (Exception ex)
69 {
70 Console.WriteLine(ex.Message);
71 Console.ReadKey();
72 }
73 finally
74 {
75 if (host.State == CommunicationState.Faulted)
76 host.Abort();
77 else
78 host.Close();
79 }
80 }
81 }
82 }
83
84
嗨,希望你能帮忙......
我正在创建一个简单的应用程序(可能是网页),它将具有简单的用户界面,并将从外部设备上传文件,当用户将设备插入PC时,应用程序/网页将通过autorun.inf启动。 Web服务将执行将文件链接到管理系统等的复杂工作。这将使不能使用文件浏览的IT文盲用户能够将文件提交到管理系统......!
我遇到的问题是,当内容类型为image / jpeg时,我的RESTful服务器会给我400错误。 它适用于text / plain或text / xml(参见博客文章)
由于 Ĵ
答案 0 :(得分:7)
您可以尝试覆盖任何内容类型,并使用IOperationBehavior将所有文件上传为application / octet-stream或text / plain。
public class WebContentTypeAttribute : Attribute, IOperationBehavior, IDispatchMessageFormatter
{
private IDispatchMessageFormatter innerFormatter;
public string ContentTypeOverride { get; set; }
public WebContentTypeAttribute(string contentTypeOverride)
{
this.ContentTypeOverride = contentTypeOverride;
}
// IOperationBehavior
public void Validate(OperationDescription operationDescription)
{
}
public void ApplyDispatchBehavior(OperationDescription operationDescription, DispatchOperation dispatchOperation)
{
innerFormatter = dispatchOperation.Formatter;
dispatchOperation.Formatter = this;
}
public void ApplyClientBehavior(OperationDescription operationDescription, ClientOperation clientOperation)
{
}
public void AddBindingParameters(OperationDescription operationDescription, BindingParameterCollection bindingParameters)
{
}
// IDispatchMessageFormatter
public void DeserializeRequest(Message message, object[] parameters)
{
if (message == null)
return;
if (string.IsNullOrEmpty(ContentTypeOverride))
return;
var httpRequest = (HttpRequestMessageProperty)message.Properties[HttpRequestMessageProperty.Name];
httpRequest.Headers["Content-Type"] = ContentTypeOverride;
}
public Message SerializeReply(MessageVersion messageVersion, object[] parameters, object result)
{
return innerFormatter.SerializeReply(messageVersion, parameters, result);
}
}
您必须修改服务合同,使其看起来像这样
[OperationContract]
[WebInvoke(Method = "POST",UriTemplate = "File/{fileName}")]
[WebContentType("application/octet-stream")]
bool UploadFile(string fileName, Stream fileContents);
虽然如果您从网页上传,数据不会以多部分/表格数据格式发布吗?