Question

lst = ['12233223','13232423','23453443']

我正在寻找这样的输出：

new_list = [{'id':'12233223', 'new_id':'d2233223'},{'id':'13232423','new_id':'d3232423'}]

但我得到了这个

[{'id':13453443,'new_id':13453443},{'id':13453443,'new_id':13453443}]

这是我的代码

lst = [{'id':'12233223'},{'id':'13232423',} {'id':'23453443'}]
d={}
new_list=[]
for each in lst:
    d['id']= each
    if len(each)==8 and each[0]==1:
    new_id = each.replace('1','d',1)
    d['new_id'] = new_id
    new_list.append(d)

Answer 1

这个更简单的版本怎么样。相反，您可以简单地将 'd' 添加到 string[1:] -

[{'id':i,'new_id':'d'+i[1:]} for i in lst]

[{'id': '12233223', 'new_id': 'd2233223'},
 {'id': '13232423', 'new_id': 'd3232423'},
 {'id': '23453443', 'new_id': 'd3453443'}]

编辑：刚刚看到您的 if 条件。更新 -

[{'id':i,'new_id':'d'+i[1:]} for i in lst if i[0] if i[0]=='1' and len(i)==8]

[{'id': '12233223', 'new_id': 'd2233223'},
 {'id': '13232423', 'new_id': 'd3232423'}]

如何迭代列表并将字典附加到另一个列表

1 个答案: