使用 Python 进行网页抓取价格

时间:2021-03-01 22:45:18

标签: python python-3.x web-scraping beautifulsoup python-requests

我正在学习以下网页 https://www.youtube.com/watch?v=nCuPv3tf2Hg&list=PLRzwgpycm-Fio7EyivRKOBN4D3tfQ_rpu&index=1 上的在线教程。我不知道我做错了什么。我在 Visual Studio 和 Jupyter 笔记本中都尝试过代码,但无济于事。

代码:

import requests
from bs4 import BeautifulSoup as bs

bURL = 'https://www.thewhiskyexchange.com/c/540/taiwanese-whisky'

headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36'}
r = requests.get('https://www.thewhiskyexchange.com/c/540/taiwanese-whisky')

soup = bs(r.content, 'lxml')

productlist = soup.find_all('div', class_='item')
productlinks = []

for item in productlist:
    for link in item.find_all('a', href=True):
        print(link['href'])

1 个答案:

答案 0 :(得分:2)

自视频发布以来,该网站的结构发生了变化。

我已在下面修复了您的代码:

import requests 
from bs4 import BeautifulSoup as bs

bURL = 'https://www.thewhiskyexchange.com/c/540/taiwanese-whisky'
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36'} 

r = requests.get(bURL, headers=headers)

soup = bs(r.text, 'html.parser')

for x in soup.find_all('li', {'class':'product-grid__item'}):
    link = x.find('a')
    print(x.text, 'https://www.thewhiskyexchange.com'+link['href'])