Question

这是我的函数，getAccountType

import { firebaseAdmin } from './index';

export const getAccountType = async (data: any, context: any) => {
    const uid = context.auth.uid;
    try{
        const snapshot = await firebaseAdmin.firestore().collection('users').doc(uid).get();
        if(snapshot.exists){
            const data = snapshot.data() as { accountType : 'youth' | 'prof', firstName : string, isProfileComplete : boolean};
            return data;
        }
        else{
            return { message : "User does not exist"};
        };
    } catch(e){
        return { message : `Failed to get user data ${e}` };
    };
};

这是我的 index.ts 文件

import * as functions from "firebase-functions";
import * as admin from 'firebase-admin';
import { helloWorld } from "./helloWorld";
import { getAccountType } from "./getAccountType";


export const firebaseAdmin = admin.initializeApp();
exports.helloWorld = functions.https.onCall(helloWorld)
exports.getAccountType = functions.https.onCall(getAccountType)

这是我收到的错误

i  functions: preparing functions directory for uploading...

Error: Error occurred while parsing your function triggers. Please ensure that index.js only exports cloud functions.

HelloWorld 函数部署得很好，但出于某种原因，firebase 认为 getAccountType 不是云函数

Answer 1

通过进行一些调整，我能够在 Firebase Cloud Functions 上部署您的代码。错误是说您只能导出函数。您不能导出 const 等声明。

要修复错误，请删除 index.ts 上的 firebaseAdmin。

index.ts

import * as functions from "firebase-functions";
import { getAccountType } from "./getAccountType";

exports.getAccountType = functions.https.onCall(getAccountType)

getAccountType.ts

import * as admin from 'firebase-admin'

export const getAccountType = async (data: any, context: any) => {
    // Your code logic
    ...
};

Firebase 没有部署我的函数，说它不是云函数

1 个答案: