我有一个这样的字符串:
$string = "1,4|2,64|3,0|4,18|";
在逗号后访问数字的最简单方法是什么?
例如,如果我有:
$whichOne = 2;
如果whichOne
等于2
,那么我想将64
放入一个字符串中,并为其添加一个数字,然后将其再次放回原来的位置(下一个)到2,
)
希望你明白!
答案 0 :(得分:1)
$numbers = explode("|", $string);
foreach ($numbers as $number)
{
$int[] = intval($number);
}
print_r($int);
答案 1 :(得分:1)
genesis'es回答修改
$search_for = 2;
$pairs = explode("|", $string);
foreach ($pairs as $index=>$pair)
{
$numbers = explode(',',$pair);
if ($numbers[0] == $search_for){
//do whatever you want here
//for example:
$numbers[1] += 100; // 100 + 64 = 164
$pairs[index] = implode(',',$numbers); //push them back
break;
}
}
$new_string = implode('|',$pairs);
答案 2 :(得分:1)
$string = "1,4|2,64|3,0|4,18|";
$coordinates = explode('|', $string);
foreach ($coordinates as $v) {
if ($v) {
$ex = explode(',', $v);
$values[$ex[0]] = $ex[1];
}
}
要查找say,2的值,您可以使用$whichOne = $values[2];
,64
答案 3 :(得分:1)
我认为像其他人建议的那样使用foreach要好得多,但你可以像下面这样做:
$string = "1,4|2,64|3,0|4,18|";
$whichOne = "2";
echo "Starting String: $string <br>";
$pos = strpos($string, $whichOne);
//Accomodates for the number 2 and the comma
$valuepos = substr($string, $pos + 2);
$tempstring = explode("|", $valuepos);
$value = $tempstring[0]; //This will ow be 64
$newValue = $value + 18;
//Ensures you only replace the index of 2, not any other values of 64
$replaceValue = "|".$whichOne.",".$value;
$newValue = "|".$whichOne.",".$newValue;
$string = str_replace($replaceValue, $newValue, $string);
echo "Ending String: $string";
这导致:
Starting String: 1,4|2,64|3,0|4,18|
Ending String: 1,4|2,82|3,0|4,18|
如果有多个索引为2,则可能会遇到问题...这只适用于第一个2的实例。
希望这有帮助!
答案 4 :(得分:1)
我知道这个问题已经回答了,但我做了一行解决方案(也许它的速度也快了):
$string = "1,4|2,64|3,0|4,18|";
$whichOne = 2;
$increment = 100;
echo preg_replace("/({$whichOne},)(\d+)/e", "'\\1'.(\\2+$increment)", $string);
在控制台中运行示例:
noice-macbook:~/temp% php 6642400.php
1,4|2,164|3,0|4,18|