用另一个变量替换字符串

Question

我有一个像这样的 shell 脚本 -

codes=('B4036' 'B9002')

query=$(cat <<EOF
WITH claims AS 
(
   SELECT code, month, patient
   FROM lines
   WHERE code = 'proc_codes'
)
EOF
)

for i in "${codes[@]}"
do
  
  sql=$(echo $query | sed -e "s/proc_codes/$i/g")

done

当我打印 sql 时，我得到

WITH claims AS ( SELECT code, month, patient FROM lines WHERE code = '\''B4036'\'' )

为什么我在 '\'' 附近收到 proc_codes？我如何让上面的行成为 -

WITH claims AS ( SELECT code, month, patient FROM lines WHERE code = 'B4036' )