Question

给定一个字母数字字符串序列，输出包含至少一个字母和一个数字的最大字符串的长度。如果不存在这样的字符串，则输出 0。

应该使用 Bash

Answer 1

使用 GNU awk：

awk 'BEGIN { map[0]="" } { for(i=1;i<=NF;i++) { if ($i ~ /[[:digit:]]/ && $i ~ /[[:alpha:]]/) { map[length($i)]=$i }  } } END { PROCINFO["sorted_in"]="@ind_num_asc";for (i in map) { len=i } print len}' <<< "this sfdsf fdgdf 6gdfgg 56gdfggf67dfgdg"

说明：

awk 'BEGIN { 
             map[0]=""                                               # Initialise an array map with a 0 string length index
           } 
           { 
             for(i=1;i<=NF;i++) {                                    # Loop through each work in the sequence of string
               if ($i ~ /[[:digit:]]/ && $i ~ /[[:alpha:]]/) { 
                  map[length($i)]=$i                                 # If the word matches a digit and it matches a alpha character, add to the map array with the length of the word as the index and the word the value
               }  
             } 
            } 
        END { 
              PROCINFO["sorted_in"]="@ind_num_asc";                   # At the end of processing the sequence, set the array ordering
              for (i in map) { 
                len=i                                                 # Loop through the array setting len to the index
              } 
              print len                                               # Print len, (the highest length)
             }' <<< "this sfdsf fdgdf gdfgg 56gdfggf67dfgdg"

给定一个字母数字字符串序列，输出最大字符串的长度

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