Question

即使用户输入了正确的单词，我在第 4 行和第 6 行中的 if 语句也会继续运行。我很困惑。有什么建议么？已经尝试让它工作一天了。

boi = input("Do you want to enter a part of a house or a word, (\"house part\" or \"word\")? ")
print(boi)
if boi != "house part":
    print("I do not understand", boi +".")
elif boi != "word":
    print("I do not understand", boi + ".")
if boi == "house part":
    hp = input("Please enter a part of a house: ")
    print(hp)
    if hp == "basement":
        print("calf")
    elif hp == "wall":
        print("skin")
    elif hp == "attic":
        print ("hip")
    elif hp == "kitchen":
        print("abdomen")
    elif hp == "study":
        print("wrist")
    else:
        print("I do not know anything about a(n)", hp + ".")
elif boi == "word":
    w = input("Please enter a word: ")
    print(w)
    if w == "attorney":
        print("macilmud")
    elif w == "chicken":
        print("sleent")
    elif w == "consider":
        print("floria")
    elif w == "application":
        print("sailinexemy")
    elif w == "prepare":
        print("capied")
    else:
        print("I do not know anything about a(n)", w + ".")

Answer 1

所有输入要么不是一个，要么不是另一个。您需要将这两者合并为一个条件，例如：

if boi not in ("house part","word"):
    print("I do not understand", boi + ".")

或者，更简单地说，在下一个条件中添加一个最后的 else:（并删除第一个）。

if boi == "house part":
    ...
elif boi == "word":
    ...
else:
    print("I do not understand", boi + ".")

Answer 2

您的代码：

if boi != "house part":
    print("I do not understand", boi +".")
elif boi != "word":
    print("I do not understand", boi + ".")

输入 house part 将导致 I do not understand house part.，因为 house part 不等于满足 word 的 elif boi != "word":。看起来您想将这两个语句合二为一：

if boi not in ("house part", "word"):

这是因为您当前的代码是这样运行的：

#user enters "house part"
if boi != "house part": 
#boi is equal to "house part" so the if returns 
#false and continues to the elif
    print("I do not understand", boi +".")
elif boi != "word":
#boi is not equal to "word" so the elif is satisfied and 
#the below statements are run.
    print("I do not understand", boi + ".")

Answer 3

当你想验证输入时，你可以使用下面的这个部分来代替：

if boi != "house part":
    print("I do not understand", boi +".")
elif boi != "word":
    print("I do not understand", boi + ".")

使用这个：

if boi != "house part" and boi != "word":
    print("I do not understand", boi +".")

为什么我的 if 语句运行不正确？

3 个答案: