Question

我有这个 JSON 结构：

const arr = [
        {
          id: "TaskStatuses",
          rows: [
            {id: "1", name: "Success"},
            {id: "2", name: "Error"},
          ]
        },
        {
          id: "Objects",
          rows: [
            {id: "1", name: "Object1"},
            {id: "2", name: "Object2"},
          ]
        },
        {
          id: "Groups",
          rows: [
            {id: "1", name: "Group1"},
            {id: "2", name: "Group2"},
          ]
        },
      ]

我需要创建具有某种条件的数组。如果我的条件正确，我将推送元素 arr.rows。

最后我想得到这个结构：

[
{
  Objects: "Object1",
  Groups: "Group1"
},
  {
    Objects: "Object2",
    Groups: "Group2"
  }
]

我尝试这样做

let sites = []
    for (let el in arr) {
            if (arr.id == "Objects") {
              for (let item of el.rows) {
                sites.push({Objects: item.name})
              }
            }
            if (arr.id == "Groups") {
              for (let item of el.rows) {
                sites.Groups = item.name
              }
            }
          }

Answer 1

您可以在新对象中映射所需的属性。

const
    data = [{ id: "TaskStatuses", rows: [{ id: "1", name: "Success" }, { id: "2", name: "Error" }] }, { id: "Objects", rows: [{ id: "1", name: "Object1" }, { id: "2", name: "Object2" }] }, { id: "Groups", rows: [{ id: "1", name: "Group1" }, { id: "2", name: "Group2" }] }],
    ids = ['Objects', 'Groups'],
    result = data.reduce((r, { id, rows }) => ids.includes(id)
        ? rows.map(({ name }, i) => ({ ...r[i], [id]: name }))
        : r,
        []
    );

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

如何遍历数组？

1 个答案: