在任何情况下，我只想在用户点击推送通知提醒的“查看”按钮时显示/加载我的应用程序

Question

这是我的AppDelegate类。在我的应用程序中，我使用的是Apple推送通知服务。我正在收到推送通知。

但问题是当我点击推送通知提醒中的“查看”按钮时，我的应用程序没有加载。

在任何情况下，我只想在用户点击推送通知提醒的“查看”按钮时显示/加载我的应用程序。

我的代码中的错误是什么，还有我要编写的代码。请帮帮我。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {


    CGRect frame = [UIScreen mainScreen].bounds;
    window = [[UIWindow alloc] initWithFrame:frame];
    window.backgroundColor = [UIColor blackColor];
    [window makeKeyAndVisible];

    splashScreen = [[SplashViewController alloc] initWithImage:[UIImage imageNamed:@"Screen.png"]];
    navigationController = [[UINavigationController alloc] initWithRootViewController:splashScreen];
    [window addSubview:navigationController.view];

    NSLog(@"Registering for push notifications...");
    [[UIApplication sharedApplication]registerForRemoteNotificationTypes:(UIRemoteNotificationTypeAlert |UIRemoteNotificationTypeBadge |
      UIRemoteNotificationTypeSound)];

    return YES;
}


- (void)application:(UIApplication *)app
didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
{
    NSString *str =
    [NSString stringWithFormat:@"Device Token=%@",deviceToken];
    NSLog(@"%@", str);
}

- (void)application:(UIApplication *)app
didFailToRegisterForRemoteNotificationsWithError:(NSError *)err

{
    NSString *str = [NSString stringWithFormat: @"Error: %@", err];
    NSLog(@"%@", str);
}


- (void)application:(UIApplication *)application
didReceiveRemoteNotification:(NSDictionary *)userInfo
{
    for (id key in userInfo) {
        NSLog(@"key: %@, value: %@", key, [userInfo objectForKey:key]);
    }
}