Question

我有两个 xls 文件，每行都属于彼此。我打算制作一个文本文件，将第二行放在那里，并用第一行命名。示例数据如下所示

data1.xls

ram
rama
rot
tab

data2.xls

myfirstattemp
mysecondattemp
mythirdattemp 
myfourthattemp

所以它看起来像这样

ram.txt (inside is myfirstattempt)
rama.txt (inside is mysecondattemp)
.
.
.

我确实尝试了不同的东西，但我无法弄清楚，看看我写了什么

import xlrd



workbook1 = xlrd.open_workbook('data1.xlsx')
workbook2 = xlrd.open_workbook('data2.xlsx')
for sheet in workbook1.sheets():
    for i in range(sheet.nrows):
for sheet in workbook2.sheets():
    for i in range(sheet.nrows):
        rowi_col0 = sheet.cell_value(i, 0)
        #print filename.format(col_0, i)
        out.save(workbook1.format('sheet.nrows', i+1))

Answer 1

你还没有说明你的错误信息是什么，所以我不得不指定一个过程。此外，您的 out.save 行将崩溃，因为没有对 out 的引用。

请注意，出于安全原因，不建议将 xlrd 用于 xlsx，仅用于 xls。建议您为 xlsx 使用像 openpyxl 这样的库。（实际上，如果您拥有最新版本的 xlrd，它甚至不会让您针对 xlsx 运行 - 因此我的代码指的是 xls）。

import xlrd

# Set the references to the workbook and sheets
workbook1 = xlrd.open_workbook('data1.xls')
workbook2 = xlrd.open_workbook('data2.xls')
sheet1 = workbook1.sheet_by_index(0)
sheet2 = workbook2.sheet_by_index(0)

# Pull the data into lists
names_for_files = [sheet1.cell_value(row,0) for row in range(sheet1.nrows)]
data_for_files = [sheet2.cell_value(row,0) for row in range(sheet2.nrows)]

# Iterate over the names
for out_index,output_name in enumerate(names_for_files):
    with open(f'{output_name}.txt', 'w') as f:
        f.write(data_for_files[out_index])

# Could zip the two lists together to tidy up the output
# Could pull the data as a dictionary for the same reason

如何将一个文件行分配给另一个文件行

1 个答案: