Question

我在这里不知所措。我有一个相当简单的事情，但似乎遇到了很多问题。我在工作中有直接的网络爬虫。人们发布请求并将其发送到队列。如果他们想查询队列中的最新信息：路由是

127.0.0.1:8080/requests/id/1.json

响应是动作（def） CrawlerController是控制器。请求是模型。

继承路线:(虽然我认为不相关）

  match 'requests/id/:id' => 'crawler#response'

这是控制器中的def：

  def response
    @request = Request.find(params[:id])
   respond_to do |format|
     #format.html { render :action => "new"}
     format.json { render :json => @request.to_json }
    end
  end

我得到的错误是堆栈级别太深。如果我看一下控制台输出：

编辑：第21行和第19行是要做的@respond和format.json

  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
  CACHE (0.0ms)  SELECT "requests".* FROM "requests" WHERE "requests"."id" = 1 LIMIT 1
Completed 500 Internal Server Error in 2688ms

SystemStackError (stack level too deep):
  app/controllers/crawler_controller.rb:21:in `response'
  app/controllers/crawler_controller.rb:19:in `response'
  app/controllers/crawler_controller.rb:21:in `response'
  app/controllers/crawler_controller.rb:19:in `response'
  app/controllers/crawler_controller.rb:21:in `response'
  app/controllers/crawler_controller.rb:19:in `response'

很奇怪啊？

Answer 1

尝试将您的方法从response重命名为其他内容。我认为Rails可能会使用response来做其他事情。

Answer 2

尝试将变量从@request重命名为其他内容。我认为Rails可能会使用@request来做其他事情。

还可以尝试将您的操作从response重命名为其他内容。我认为Rails可能会使用response来做其他事情。

Ruby应用程序响应直到堆栈太深

2 个答案: