继承类中的打字稿推断方法返回类型

Question

我正在尝试创建一个基类，其属性为同一类中另一个方法的返回类型，这可以在子类中更改它的类型：

abstract class Base {
    public get = {
        ...this.getBase(),
        hello() {}
    }

    protected abstract getBase<T extends object>(): T;
}

class InheritBase extends Base {
    // Error: '{ hello2(): number; }' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'object'
    protected getBase() {
        return {
            hello2() {return 3},
        }
    }
}

class InheritBase2 extends Base {
    // Error: '{ differentHello(): number; }' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'object'
    protected getBase() {
        return {
            differentHello() {return 4},
        }
    }
}

const c = new InheritBase();
// ok
c.get.hello();
// Error: hello2 doesn't exist on property get
c.get.hello2();

const d = new InheritBase2();
// ok
d.get.hello();
// Error: differentHello doesn't exist on property get
d.get.differentHello();

这个想法是为了避免在每个子类中重新定义属性 get，同时也在派生类中获取实际类型。 如何实现？