请参阅此代码:
public class multiply
{
public Thread myThread;
public int Counter
{
get;
private set;
}
public string name
{
get;
private set;
}
public void RunConsolePrint()
{
lock(this)
{
RunLockCode("lock");
}
}
private void RunLockCode(string lockCode)
{
Console.WriteLine("Now thread "+lockCode+" " + name + " has started");
for (int i = 1; i <= Counter; i++)
{
Console.WriteLine(lockCode+" "+name + ": count has reached " + i + ": total count is " + Counter);
}
Console.WriteLine("Thread " + lockCode + " " + name + " has finished");
}
public multiply(string pname, int pCounter)
{
name = pname;
Counter = pCounter;
myThread = new Thread(new ThreadStart(RunConsolePrint));
}
}
这是测试运行代码:
static void Main(string[] args)
{
int counter = 50;
multiply m2 = new multiply("Second", counter);
multiply m1 = new multiply("First", counter);
m1.myThread.Start();
m2.myThread.Start();
Console.ReadLine();
}
我希望m2
必须在m1
开始执行之前从头到尾执行,反之亦然,因为lock
语句。但我发现的结果是首先锁定锁定而第二锁定是一起混合,即类似这样的事情
Now thread lock First has started
Now thread lock Second has started
lock First: Count has reached 1: total count is 50
lock First: Count has reached 2: total count is 50
lock Second: Count has reached 1: total count is 50
我做错了什么?
答案 0 :(得分:21)
代码的每个实例都锁定在不同的对象上。您的锁对象需要在所有实例之间共享 - 使其成为静态类变量。
private static object syncRoot = new object();
public void RunConsolePrint()
{
lock(syncRoot)
{
RunLockCode("lock");
}
}