我是struts 2的新手,我不断收到此错误信息'没有结果为动作定义com.jjpeople.action.HelloAction和结果成功',而我认为我已经正确地引用了它。可能是什么问题?< / p>
struts.xml中
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>
<constant name="struts.devMode" value="false" />
<constant name="struts.enable.DynamicMethodInvocation" value="false" />
<package name="tutiworks" extends="struts-default">
<action name="index">
<result>/index.jsp</result>
</action>
<action name="hello" class="com.jjpeople.action.HelloAction" method="execute">
<result name="success">/welcome.jsp</result>
</action>
</package>
</struts>
的index.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="s" uri="/struts-tags" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Basic Struts 2 Application - Welcome</title>
</head>
<body>
<h1>Welcome To Struts 2!</h1>
<p><a href="<s:url action='hello'/>">Hello World</a></p>
</body>
</html>
动作类
package com.jjpeople.action;
import com.jjpeople.model.Hello;
import com.opensymphony.xwork2.ActionSupport;
public class HelloAction extends ActionSupport
{
private static final long serialVersionUID = 1L;
private Hello hello;
public String execute() throws Exception
{
hello = new Hello();
return SUCCESS;
}
public Hello getMessage()
{
return hello;
}
public void setMessage(Hello hello)
{
this.hello = hello;
}
}
答案 0 :(得分:0)
在您的xml文件中
<action name="hello" class="com.jjpeople.action.HelloAction" method="execute"> <result name="success">/welcome.jsp</result> </action>
结果名称是“成功”,但在你的Action类中你返回“SICCESS”变量。所以请检查SUCCESS变量值。
答案 1 :(得分:0)
结果是struts.xml和Action没有等于。所以返回了你没有定义的异常。