Question

我想编写一个函数，当用户回答 Y 时，机器人发送消息“重新加载幸福”，否则，如果用户回答 N，则发送消息晚安。我试图运行此代码，该代码回复“嗨”，但之后，当我输入 Y 或 N 时，机器人无法回复。我的代码示例：

@client.event
async def on_message(message):
  if message.author == client.user:
    return

  # if message.content.startswith('$inspire'):
  #   quote = get_quote()
  #   await message.channel.send(quote)

  if message.content.startswith('hi'): # Delete this after testing
    await message.channel.send('Congratulations! Your Disgotchi is hatched! (Play around? : Y/N)')
    if message.content.includes('y', 'Y'):
      await message.channel.send('Happiness reloaded! (　＾Θ＾)❤️')
    elif message.content.includes('n', 'N'):
      await message.channel.send('I will go to bed, good night!')

Answer 1

应该做你想做的您所要做的就是将 id 存储在回调之外，期望同一回调中的另一条消息随着消息更新的变化而无用

import discord
from discord.ext.commands import Bot
bot = Bot(command_prefix='$')

y_users = set() # set is best for this

@bot.event
async def on_ready():
    print(f'Bot connected as {bot.user}')
    
@bot.event
async def on_message(message):
    if message.content == 'hi':
        await message.channel.send('Congratulations! Your Disgotchi is hatched! (Play around? : Y/N)')
        y_users.add(message.author.id) # saving the id
    # checking if id is in set which means user sent hello previously
    elif (message.content.startswith('y', 'Y') and message.author.id in y_users):
        await message.channel.send('Happiness reloaded! (　＾Θ＾)❤️')
        y_users.remove(message.author.id)
    elif (message.content.startswith('n', 'N') and message.author.id in y_users):
      await message.channel.send('I will go to bed, good night!')
      y_users.remove(message.author.id)

bot.run("token")

如果它符合您的要求，请将其标记为正确的解决方案

如何为不和谐机器人编码是/否功能

1 个答案: