Question

我想点击下一页直到没有更多页面，但它没有点击。

返回错误：raise exception_class(message, screen, stacktrace)

StaleElementReferenceException：过时的元素引用：元素未附加到页面文档

我的代码：

提前致谢！

driver.get('http://www.chinamoney.com.cn/chinese/zjfxzx/?tbnm=%E6%9C%80%E6%96%B0&tc=null&isNewTab=1')
driver.implicitly_wait(10)
driver.refresh()
driver.implicitly_wait(10)
wait = WebDriverWait(driver, 5)
datefield_st = wait.until(EC.element_to_be_clickable((By.ID, "pdbp-date-1")))
datefield_st.click()
select_st = Select(wait.until(EC.element_to_be_clickable((By.CLASS_NAME, "ui-datepicker-year"))))
select_st.select_by_visible_text("2021")
select2 = Select(wait.until(EC.element_to_be_clickable((By.CLASS_NAME, "ui-datepicker-month"))))
select2.select_by_value("1")
day=1
wait.until(EC.element_to_be_clickable((By.XPATH, "//td[@data-handler='selectDay']/a[text()='{}']".format(str(day))))).click()
datefield_ed = wait.until(EC.element_to_be_clickable((By.ID, "pdbp-date-2")))
datefield_ed.click()
select_ed = Select(wait.until(EC.element_to_be_clickable((By.CLASS_NAME, "ui-datepicker-year"))))
select_ed.select_by_visible_text("2021")
select2 = Select(wait.until(EC.element_to_be_clickable((By.CLASS_NAME, "ui-datepicker-month"))))
select2.select_by_value("1")
day=1
wait.until(EC.element_to_be_clickable((By.XPATH, "//td[@data-handler='selectDay']/a[text()='{}']".format(str(day))))).click()
driver.find_element_by_link_text("查询").click()
while True:
    driver.implicitly_wait(10)
    links=[link.get_attribute('href') for link in driver.find_elements_by_xpath("//a[contains(@title,'同业存单') and not(contains(@title,'申购说明')) and not(contains(@title,'公告'))]")]
    titles = [title.text for title in driver.find_elements_by_xpath("//a[contains(@title,'中期票据') and not(contains(@title,'申购说明')) and not(contains(@title,'公告'))]")]
    dates = [date.text for date in driver.find_elements_by_xpath('//*[@class="san-grid-r text-date"]')]
    driver.implicitly_wait(10)
    for link, title,date in zip(links, titles,dates):
        dataframe = pd.DataFrame({'col1':date,'col2':title,'col3':link},index=[0])
        dataframe.to_csv('Chinamoney.csv',mode='a+',header=False,index=False,encoding='utf-8-sig')
        print(link,title,date)
    try:
        driver.find_element_by_xpath('//*[contains(@class, "page-next")]').click()
    except:
        print('No more pages')

Answer 1

您将两个类名传递给选择器，而不允许按类名搜索。要么试试

(By.CLASS_NAME, 'page-next')

或

(By.CSS_SELECTOR, '.page-btn.page-next')

您的 element 和 icon 也选择相同的元素。所以你不需要定义icon。只需使用 element.click()

Answer 2

您正在使用：

driver.find_element_by_xpath('//*[contains(@class, "page-next")]').click()

试试：

element = driver.find_element_by_xpath('//*[contains(@class, "page-next")]')
driver.execute_script("arguments[0].click();", element)

如果这样不行，你可以尝试获取url/link的值并存储起来，之后你可以去这个url或者做你想做的事，而无需点击它。

Python Selenium 无法点击下一页按钮

2 个答案: