Question

list1= ['ALEX', 'George', 'shyam']

list2= ['George','Ram', 'shyam']

output=['Alex', 'George','Shyam','Ram']

我试过喜欢它。

    list1=['ALEX', 'George', 'shyam']
    list2=['George','Ram', 'shyam']
    output=list1
    for j in list2:
        for i in list1:
            if str(j)!=str(i):
                output=output+[j]
    print(output)

但是，这是错误的。请帮助我知道如何处理上述问题！我是编程的菜鸟。提前致谢。

Answer 1

list1=['ALEX', 'George', 'shyam']
list2=['George','Ram', 'shyam']
res = list1.copy()

for el in list2:
    if el not in res:
        res.append(el)

print(res)

Answer 2

要合并两个列表，请使用：

list1 = ['ALEX', 'George', 'shyam']
list2 = ['George','Ram', 'shyam']
resultList= list(set(list1 ) | set(list2))
print(resultList)

输出： ['shyam', 'George', 'ALEX', 'Ram']

Answer 3

集合不能有重复项。因此，将列表转换为集合并返回到列表可以消除所有重复项。因此，添加您的列表并将较大的列表转换为一组：

list1= ['ALEX', 'George', 'shyam']
list2= ['George','Ram', 'shyam']
result = set(list1 + list2)
print(list(result))

#prints ['Ram', 'George', 'ALEX', 'shyam']

Answer 4

这将给出与问题中所述相同的顺序

list1= ['ALEX', 'George', 'shyam']

list2= ['George','Ram', 'shyam']

#output=['Alex', 'George','Shyam','Ram']

output=[x.capitalize() for x in list1] # Copy list but capitalize each string e.g. ALEX -> Alex
for name in list2: # iterate through list2
    if name.capitalize() not in output: # if it is not already in output, append it
        output.append(name)
        
print(output)

如何合并两个列表而不包括python中两个列表中共有的元素

4 个答案: