我正在尝试使用此代码获取Linux系统的MAC地址:
try {
ip = InetAddress.getLocalHost();
NetworkInterface network = NetworkInterface.getByInetAddress(ip);
byte[] mac = network.getHardwareAddress();
// System.out.print("Current MAC address: ");
for (int i = 0; i < mac.length; i++) {
is = is + Integer.parseInt(
String.format("%02X%s", mac[i], (i < mac.length - 1) ? "" : ""),16);
}
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (SocketException e) {
e.printStackTrace();
}
但它只是崩溃了...有谁知道为什么?
答案 0 :(得分:6)
您可能有多个网络接口,我不会指望接口的名称。我建议你查看所有接口,找一个有MAC地址的接口。 您可以将此示例用作基线:
try {
Enumeration<NetworkInterface> networkInterfaces = NetworkInterface.getNetworkInterfaces();
while(networkInterfaces.hasMoreElements())
{
NetworkInterface network = networkInterfaces.nextElement();
System.out.println("network : " + network);
byte[] mac = network.getHardwareAddress();
if(mac == null)
{
System.out.println("null mac");
}
else
{
System.out.print("MAC address : ");
StringBuilder sb = new StringBuilder();
for (int i = 0; i < mac.length; i++)
{
sb.append(String.format("%02X%s", mac[i], (i < mac.length - 1) ? "-" : ""));
}
System.out.println(sb.toString());
break;
}
}
} catch (SocketException e){
e.printStackTrace();
}
答案 1 :(得分:3)
从您的评论中,network
显然是null
,这意味着getByInetAddress()
无法找到具有该IP地址的接口(请参阅JavaDocs:http://download.oracle.com/javase/1.5.0/docs/api/java/net/NetworkInterface.html#getByInetAddress(java.net.InetAddress))。
答案 2 :(得分:2)
只是对盖伊代码的一个小修改:
public String searchForMac() throws SocketException {
String firstInterface = null;
Map<String, String> addressByNetwork = new HashMap<>();
Enumeration<NetworkInterface> networkInterfaces = NetworkInterface.getNetworkInterfaces();
while(networkInterfaces.hasMoreElements()){
NetworkInterface network = networkInterfaces.nextElement();
byte[] bmac = network.getHardwareAddress();
if(bmac != null){
StringBuilder sb = new StringBuilder();
for (int i = 0; i < bmac.length; i++){
sb.append(String.format("%02X%s", bmac[i], (i < bmac.length - 1) ? "-" : ""));
}
if(sb.toString().isEmpty()==false){
addressByNetwork.put(network.getName(), sb.toString());
System.out.println("Address = "+sb.toString()+" @ ["+network.getName()+"] "+network.getDisplayName());
}
if(sb.toString().isEmpty()==false && firstInterface == null){
firstInterface = network.getName();
}
}
}
if(firstInterface != null){
return addressByNetwork.get(firstInterface);
}
return null;
}
此代码已经在Windows,Linux(Ubuntu)和Mac OS X上测试成功。
因为网络可以为null,所以我忽略所有空的情况,并且我也忽略空地址。我想如果我们不这样做,我们会看到崩溃。我选择了第一个找到的地址并且它有效,但可能是错误的,所以只需测试一下。