Question

我想在那些不存在的集群名称中填充 0。与预期的输出一样，我在最后一行添加了 0，因为我没有在数据框中找到任何结果。 输入：

到目前为止我已经尝试过

#I have made clusters according to the requirement and making sum of it
# output of this code is given above
d_inv = {x: k for k, v in dict1.items() for x in v}
df = df['PII Count'].groupby(df['PII'].map(d_inv)).sum() \
        .rename_axis('Cluster names') \
        .reset_index(name='Total count')
print(df)

Answer 1

如果顺序无关紧要，请使用重新索引并使用 dict1 中的键：

(df['PII Count'].groupby(df['PII'].map(d_inv)).sum().rename_axis('Cluster names')
                .reindex(dict1.keys(),fill_value=0)
                .reset_index(name='Total count'))

   Cluster names  Total count
0  Personal Info          270
1    Health Info            0
2   Network Info           94
3    Others Info           59
4   Finance Info            1

如果订单很重要：

m = df['PII'].map(d_inv)
out = df['PII Count'].groupby(m).sum()
out = (out.reindex(out.index.union(set(dict1.keys()).difference(m),sort=False),
        fill_value=0)
        .rename_axis('Cluster names')
        .reset_index(name='Total count'))

print(out)

   Cluster names  Total count
0   Finance Info            1
1   Network Info           94
2    Others Info           59
3  Personal Info          270
4    Health Info            0

如何在熊猫数据框中填充 0？

1 个答案: