Question

我有一个格式的字典：

d = {'award1' : { 'nominees': ['name1', 'name2'],
                  'presenters': ['name3', 'name4'],
                  'winner' : 'name1'
                }
     'award2' : { 'nominees': ['name5', 'name6'],
                  'presenters': ['name7', 'name8'],
                  'winner' : 'name6'
                }
    }

我正在尝试创建一个分隔值的字典列表，即结果应该是：

my_list = [ { 'award1': ['name1','name2'], 'award2': ['name5','name6'] },
            { 'award1': ['name3','name4'], 'award2': ['name7','name8'] },
            { 'award1': 'name1', 'award2': 'name6' }
          ]

有没有办法通过单行列表理解来做到这一点？

到目前为止我尝试过的：

lst = [{key:val['nominees'], key:val['presenters'], key:val['winner']} for key, val in d.items()]

我的代码使用普通的“for”循环：

nominees, winner, presenters = {}, {}, {}
    for key, val in d.items():
        nominees[key] = val['nominees']
        winner[key] = val['winner']
        presenters[key] = val['presenters']
lst = [nominees, winner, presenters]

Answer 1

这是一个列表推导 + 字典推导版本的单行代码来实现这一点：

d = {
    'award1' : { 
        'nominees': ['name1', 'name2'],
        'presenters': ['name3', 'name4'],
        'winner' : 'name1'
     },
     'award2' : {
         'nominees': ['name5', 'name6'],
         'presenters': ['name7', 'name8'],
         'winner' : 'name6'
      }
}

# List of keys to maintain the order of elements in the desired list
nested_keys = ['nominees', 'presenters', 'winner']

# In Python 3.7+: If the insertion order of key in initial dict is same as
#                 order of desired list, we can use this to make it more generic
# nested_keys = list(d.values())[0].keys()

new_list = [{k: d[k][key] for k in d.keys()} for key in nested_keys]

new_list 的位置：

[
    {'award1': ['name1', 'name2'], 'award2': ['name5', 'name6']}, 
    {'award1': ['name3', 'name4'], 'award2': ['name7', 'name8']}, 
    {'award1': 'name1', 'award2': 'name6'}
]

使用列表理解从字典中创建字典列表

1 个答案: