我一直在从事接受用户姓名和电话号码的 flutter 项目,但是当我保存它时,它显示响应 500,但从邮递员那里它工作正常。
但是这里是flutter的代码
void RegisterUsers(String names, String phone) async{
String urlInser = "https://hmmmiii.com/api/addUser";
Map<String, String> headers = {
'Content-Type': 'application/json',
//'Accept': 'application/json',
};
final msg = jsonEncode({"Name":"$names","PhoneNumber":"$phone"});
var response = await http.post(urlInser,
headers: headers,
body: msg);
print(response.statusCode);
if (response.statusCode == 200) {
print('User Registered');
} else {
print('Unsuccessful');
}
姓名和电话是 textController 值谢谢。
答案 0 :(得分:1)
在邮递员中,您将请求作为表单数据发送,但在您的代码中,您将其作为简单的 JSON 发送。
您必须改用 MultipartRequest
。
final url = 'your url';
final request = http.MultipartRequest('POST', Uri.parse(url))
..fields['Name'] = 'some name'
..fields['PhoneNumber'] = 'some phonenumber';
final response = await request.send();
final responseBody = await response.stream.bytesToString();
print('RESPONSE BODY: $responseBody');